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andrezito [222]
3 years ago
8

A copy machine makes

Mathematics
1 answer:
IrinaK [193]3 years ago
7 0
This problem can be represented in a formula with fractions. To make it more simple, we are converting 5m30s to just pure seconds, which = 154 copies in 330 seconds.

You set up the formula like this: 154/330 = x/60. (it is x/60 because you want to know the x amount of copies per 60 seconds)

Cross multiply, you get 330x = 9240. Divide both sides by 330, you get:

 x = 28 copies.

The final answer is 28 copies per minute
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The table shows values for functions f(x) and g(x) .
Rama09 [41]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
Find the perimeter of the image bellow: A:32.1 units B: 35.8 units C: 37.6 units D: 39.2 units
masha68 [24]
A is the closest I got. My answer was 32.665 using thousandth place. I found the perimeter by adding up the lengths. I found all of the lengths by using pathat oran theorem.
7 0
3 years ago
19 is 50% of what number
RSB [31]

If 19 is half (50%) of something, find that number you would just have to multiply 19 by 2.

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6 0
3 years ago
Without drawing the graph of the equation, determine how many points the parabola has in common with the x-axis and whether its
Ber [7]
We are given with th equation <span>y = 3x2 – 12x + 12. In this respect, we expect that this is a parabola and that the vertex does not lie on (0,0). Since the power or degree is 2, it is expected that per value of y, there are two equivalent x's in the plot. You can verify it in the graph.</span>
3 0
3 years ago
collect data (in decibels) of 10 different things in term of loudness. Arrange the data in ascending order &amp; find mean, medi
ss7ja [257]
Whisper-20dB
Quiet Residence-30dB
Soft stereo in Residence-40dB
Average Speech-60dB
Cafeteria-80dB
Pneumatic Jackhammer-90dB
Loud crowd noise-100dB
Accelerating Bike-100dB
Rock concert-120dB
Jet Engine (75 ft away)-140dB

(1)Mode=100dB (since 100 is occurring the maximum no. of times, i.e. it has the highest frequency of 2)
(2)Mean=sum of observations/Total number of observations
=(20+30+40+60+80+90+100+100+120+140)/10
=770/10=10dB
(3)Median= 1/2[{n/2}th observation + {(n/2)+1}th observation], where, n=total no. of observations
So, 1/2[{10/2}th observation + {(10/2)+1}th observation]
=1/2[5th observation+6th observation]
=1/2[80+90]                    [Because:5th observation=80dB and 6th=90dB]
=1/2(170)
=85
Therefore, median=85dB

6 0
4 years ago
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