Delta math please help

Mathematics

2 answers:

Liula [17]2 years ago

3 0

10y-6z

10×5=50

6×3=18

50-18=32

adoni [48]2 years ago

3 0

<h3>Given</h3>

y= 5, z= 3

<h3>Equation</h3>

10y - 6z

<h3>Solution</h3>

{Applying The Values}

10y - 6z

=10×5 - 6×3

=50 - 18

= 32

<h3>Hope This Helps You</h3>

You might be interested in

Pls help it due ASAP <br> Show workings <br> Pleaseeeeeeeeeeeee

Talja [164]

D
5 + 29 = 34/2 = 17
7 - 15 = -8/2 = -4
(17,-4)

3 0

2 years ago

F(x) = x(2x/2)/x(x+5)(x+6)^2 <br><br> Find the vertical asymptotes?

Alex Ar [27]

Answer:

x = -5, x = -6

Step-by-step explanation:

After canceling common terms from numerator and denominator, there are two factors remaining in the denominator that can become zero. The vertical asymptotes are at those values of x.

$\displaystyle F(x)=\frac{x\frac{2x}{2}}{x(x+5)(x+6)}=\frac{x}{(x+5)(x+6)}$

The denominator will be zero when ...

x + 5 = 0 . . . . at x = -5

x + 6 = 0 . . . . at x = -6

7 0

3 years ago

A scientist inoculates mice, one at a time, with a disease germ until he finds 3 that have contracted the disease. If the prob

UkoKoshka [18]

Answer:

The probability that 8 mice are required is 0.2428.

Step-by-step explanation:

Given : A scientist inoculates mice, one at a time, with a disease germ until he finds 3 that have contracted the disease. If the probability of contracting the disease is two sevenths.

To find : What is the probability that 8 mice are required? The probability that that 8 mice are required is nothing ?

Solution :

Applying binomial distribution,

$P(X=r)=^nC_r p^rq^{n-r}$