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luda_lava [24]
3 years ago
12

Delta math please help

Mathematics
2 answers:
Liula [17]3 years ago
3 0

10y-6z

10×5=50

6×3=18

50-18=32

adoni [48]3 years ago
3 0
<h3>Given</h3>

y= 5, z= 3

<h3>Equation</h3>

10y - 6z

<h3>Solution</h3>

{Applying The Values}

10y - 6z

=10×5 - 6×3

=50 - 18

= 32

<h3>Hope This Helps You</h3>
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A hot air ballon ascended at the rate of 400 dreams per hot for 3 hours and 15 min. What was the total distance that the ballon
alexandr1967 [171]
If it is 400 m/s then it's the answer

v= s/t
400m/s= s/11700 195×60=11,700 sec
s= 400 × 11700
s= 4,680,000 m/s ^2

11,700×400=4,680,000
4 0
3 years ago
The amount of simple interest earned I, on an investment over a fixed amount of time ????, is jointly proportional to the princi
AleksAgata [21]

Answer:$920

Step-by-step explanation:

Since the variation is joint, I=KPr where k is the constant of proportionality.

Plugging in the values of I=$375, P=$1500 and r=5% in the equation I=KPr, the value of k can be calculated. Hence, the formula connecting the three quantities (I,P and r) can be generated.

375 = K (1500×5)

Making k the subject of change,

K = 375/(1500×5)

K=1/20

Formula connecting the three quantities :I =Pr/20

when P=$2300, r=8%,

I = (2300×8)/20

I = $920

3 0
3 years ago
Which decimals are less than –2.08?
AVprozaik [17]
Would it be C? im not too sure but thats my guess =) 
4 0
3 years ago
Consider the expression 635 , 943 ÷ 77 635,943÷77. Complete the equation below by estimating the dividend and divisor in the exp
Margarita [4]

Answer:

See below

Step-by-step explanation:

<u>We can estimate the dividend and divisor as follows:</u>

  • 635943 ÷ 77 =
  • 636000 ÷ 80 =
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Estimate is 8000

5 0
3 years ago
The owner of a construction company would like to know if his current work teams can build room additions quicker than the time
frez [133]

Answer:

The claim that the current work teams can build room additions quicker than the time allotted for by the contract has strong statistical evidence.

Step-by-step explanation:

We have to test the hypothesis to prove the claim that the work team can build room additions quicker than the time allotted for by the contract.

The null hypothesis is that the real time used is equal to the contract time. The alternative hypothesis is that the real time is less thant the allotted for by the contract.

H_0: \mu=0\\\\H_1: \mu

The significance level, as a storng evidence is needed, is α=0.01.

The estimated standard deviation is:

s_M=\frac{s}{\sqrt{n}}=\frac{0.2}{\sqrt{16}} =0.2/4=0.05

As the standard deviation is estimated, we use the t-statistic with (n-1)=15 degrees of freedom.

For a significance level of 0.01, right-tailed test, the critical value of t is t=2.603.

Then, we calculate the t-value for this sample:

t=\frac{x-\mu}{s_M} =\frac{-0.32-0}{0.05}= -6.4

As the t-statistic lies in the rejection region, the null hypothesis is rejected. The claim that the current work teams can build room additions quicker than the time allotted for by the contract has strong statistical evidence.

8 0
4 years ago
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