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mylen [45]
3 years ago
5

Results from previous studies showed 79% of all high school seniors from a certain city plan to attend college after graduation.

A random sample of 200 high school seniors from this city reveals that 162 plan to attend college. Does this indicate that the percentage has increased from that of previous studies? Test at the 5% level of significance. What is your conclusion? A. Cannot determine B. More seniors are going to college C. Reject H0. There is enough evidence to support the claim that the proportion of students planning to go to college is now greater than .79. D. Do not reject H0. There is not enough evidence to support the claim that the proportion of students planning to go to college is greater than .79.
Mathematics
1 answer:
Shkiper50 [21]3 years ago
4 0

Answer:

Do not reject H_0. There is not enough evidence to support the claim that the proportion of students planning to go to college is greater than 0.79.

Step-by-step explanation:

The random sample reveals that 162/200 = 0.81 = 81% plan to attend college, so we are tempted to try and refute the 79% established by previous studies.

As the sample consists of “yes-no” answers, it can be modeled with a binomial distribution.

Now let's establish the hypothesis.

H_0: The probability that a school senior from a certain city plan attends college after graduation is 0.79 (79%)

H_a:  The probability that a school senior from a certain city plan attends college after graduation is greater than 0.79

The binomial distribution we are going to use is the model for H_0

P(k,200)=\binom{200}{k}0.79^k0.21^{200-k}

where P(k,200) is the probability of getting exactly k “yes” in 200 interviews.

Since the level of significance is 5% and in the sample we got 162 “yes”, we want to show that  

S = P(1,200) + P(2,200)+P(3,300)+...+P(162,200) is greater than 0.95.

If it is, then we can refute the null hypothesis and accept 0.81 as the new probability.

We can use either a <em>cumulative binomial distribution</em> table or the computer and we find that S=0.7807.

Since S<0.95 we cannot refute H_0

<em>It is worth noticing the the critical value here is 167. That is to say, if we had obtained 167 “yes” instead of 162, we could have rejected the null. </em>

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Anon25 [30]

Answer:

(a) The probability that a randomly selected U.S. adult uses social media is 0.35.

(b) The probability that a randomly selected U.S. adult is aged 18–29 is 0.22.

(c) The probability that a randomly selected U.S. adult is 18–29 and a user of social media is 0.198.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = an US adult who does not uses social media.

<em>Y</em> = an US adult between the ages 18 and 29.

<em>Z</em> = an US adult between the ages 30 and above.

The information provided is:

P (X) = 0.35

P (Z) = 0.78

P (Y ∪ X') = 0.672

(a)

Compute the probability that a randomly selected U.S. adult uses social media as follows:

P (US adult uses social media (<em>X'</em><em>)</em>) = 1 - P (US adult so not use social media)

                                                   =1-P(X)\\=1-0.35\\=0.65

Thus, the probability that a randomly selected U.S. adult uses social media is 0.35.

(b)

Compute the probability that a randomly selected U.S. adult is aged 18–29 as follows:

P (Adults between 18 - 29 (<em>Y</em>)) = 1 - P (Adults 30 or above)

                                            =1-P(Z)\\=1-0.78\\=0.22

Thus, the probability that a randomly selected U.S. adult is aged 18–29 is 0.22.

(c)

Compute the probability that a randomly selected U.S. adult is 18–29 and a user of social media as follows:

P (Y ∩ X') = P (Y) + P (X') - P (Y ∪ X')

                =0.22+0.65-0.672\\=0.198

Thus, the probability that a randomly selected U.S. adult is 18–29 and a user of social media is 0.198.

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3 years ago
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Answer:

A lot of work, but CD=$15, Premium=$35, and Deluxe=$85

4 0
3 years ago
This is math pls help 3x + 2(5x − 7)
Ira Lisetskai [31]

Answer: 13x - 14

Step-by-step explanation:

3x + 10x - 14

13x -14

4 0
3 years ago
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17. Solve the equation using square roots. x^2 + 5 = 41 a.+-36 b.no real number solutions c.6 d.+-6
Kipish [7]
Solve your equation step-by-step.

x^2+5=41

Subtract 5 from both sides.

x^2+5−5=41−5

x^2=36

Take square root.

x=±√36

x=6

or

x=−6

So your answer suppose to be C and D.
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5 0
3 years ago
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Vinil7 [7]

Answer:

270.3\ ft

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the right triangle ADE

Find the value of h1

See the attached figure

h1=AD

tan(25\°)=\frac{h_1}{180}

Solve for h1

h_1=(180)tan(25\°)\\h_1=83.94\ ft

step 2

In the right triangle ABC

Find the value of h2

See the attached figure

h2=BC

tan(46\°)=\frac{h_2}{180}

Solve for h2

h_2=(180)tan(46\°)\\h_2=186.40\ ft

step 3

Find the height of the neighboring building

we know that

The height of the neighboring building is equal to

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substitute the values

h=83.94+186.40=270.34\ ft

Round to the nearest tenth of a foot

h=270.3\ ft

7 0
3 years ago
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