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2 years ago

Another problem please look!

Mathematics

1 answer:

kicyunya [14]2 years ago

4 0

I think the answer is 917. Hope this help you good luck.

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The number of miles Melody rides her bicycle, m, varies directly with the amount of time spent riding the bike, t. When Melody b

natta225 [31]

It is A.

"When Melody bikes for 1.5 h, she travels 10.5 mi.", therefore her speed is 10.5/1.5 = 7 mi/hr. So the right equation is <span>m = 7t.</span>

7 0

3 years ago

How do you find midpoint for geometry

igor_vitrenko [27]

Use this formula (x1+x2 over 2, y1+y2 over 2)

7 0

3 years ago

B is the midpoint of AC and AC=8r-20,and AB=3x-1<br> Find BC

muminat

Answer:

BC = 26

Step-by-step explanation:

since B is the midpoint of AC, then AB = BC

AC = 8x - 20 & AB = 3x - 1

AC = AB + BC or 2AB

8x - 20 = 2(3x - 1)

8x - 20 = 6x - 2

subtract 6x form each side

2x - 20 = -2

add 20 to each side

2x - 20 + 20 = -2 + 20

2x = 18

x = 9

BC = 3x - 1

BC = 27 - 1

BC = 26

AC = 52

6 0

3 years ago

When v=5 and m=-4, evaluate: 4v2-m2

lions [1.4K]

Answer:

Step-by-step explanation:

4v^2 - m^2

let v=5 and m=-4

4 * (5)^2 - (-4)^2

4* (25) - (16)

100 - 16

8 0

3 years ago

A consumer group has determined that the distribution of life spans for gas ranges (stoves) has a mean of 15.0 years and a stand

Art [367]

Answer:

b. Mean = 1.6 years, standard deviation - 0.92 years, shape: approximately Normal.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction of normal Variables:

When we subtract normal variables, the mean is the subtraction of the means, while the standard deviation is the square root of the sum of the variances.

A consumer group has determined that the distribution of life spans for gas ranges (stoves) has a mean of 15.0 years and a standard deviation of 4.2 years. Sample of 35:

This means that:

$\mu_G = 15$