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zalisa [80]
3 years ago
13

The cost of a repair, which depends on the hours of labor it takes to make the

Mathematics
1 answer:
klio [65]3 years ago
7 0

Answer:

I think it's B. Hours(cost) = $200 but I could be wrong

You might be interested in
Please help me <br>find f(x+h)​
Kay [80]

Answer:

f(x) = -2x+5

f(x+h) = -2x -2h +5

g(x) = -4x-2

g(x+h) = -4x -4h -2

h(x) = 4x^2+1

h(x+h) = 4(x+h)^2 +1 = 4x^2 +8xh + 4h^2 +1

Q(x) = -3x^2 +4

Q(x+h) = -3(x+h)^2 +4 = -3x^2 -3h^2 -6xh + 4

3 0
2 years ago
Billy says that he can add 23 and 40 without regrouping is Bill correct how do you know
bija089 [108]
Yes he is correct because if you do the algorithm, 0+3=3 and 20+40=60 and 60+3=63. There is no regrouping needed.
6 0
3 years ago
Parallel lines s and t are cut by a transversal r. ​
AURORKA [14]

Answer:

the answer is <3 and 5

because they add up to 180

4 0
3 years ago
Y=1/2×-16 y=-2/3×+12 what is value of x ?
larisa86 [58]

Answer:

Is equal 54

Step-by-step explanation:

6 0
3 years ago
12What mistake did the student make when solvingtheir two-step equation?(a)b) If correctly solved what should the value of be?
mixas84 [53]

Given the equation:

\frac{x}{6}+3=-18

(a) You can identify that the student applied the Subtraction Property of Equality by subtraction 3 from both sides of the equation:

\frac{x}{6}+3-(3)=-18-(3)

However, the student made a mistake when adding the numbers on the right side.

Since you have two numbers with the same sign on the right side of the equation, you must add them, not subtract them and use the same sign in the result. Then, the steps to add them are:

- Add their Absolute values (their values without the negative sign).

- Write the sum with the negative sign.

Then:

\frac{x}{6}=-21

(b) The correct procedure is:

1. Apply the Subtraction Property of Equality by subtracting 3 from both sides (as you did in the previous part):

\begin{gathered} \frac{x}{6}+3-(3)=-18-(3) \\  \\ \frac{x}{6}=-21 \end{gathered}

2. Apply the Multiplication Property of Equality by multiplying both sides of the equation by 6:

\begin{gathered} (6)(\frac{x}{6})=(-21)(6) \\  \\ x=-126 \end{gathered}

Hence, the answers are:

(a) The student made a mistake by adding the numbers -18 and -3:

-18-3=-15\text{ (False)}

(b) The value of "x" should be:

x=-126

4 0
1 year ago
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