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3 years ago

12

What's the value of given expression

" title=" \sqrt{56 + 140} " alt=" \sqrt{56 + 140} " align="absmiddle" class="latex-formula">

1 answer:

kifflom [539]3 years ago

6 0

Answer:

<h2>14</h2>

Step-by-step explanation:

$\sqrt{56 + 140} \\ = \sqrt{196} \\ = 14$

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In ΔGHI, g = 2.7 inches, h = 6.6 inches and ∠I=58°. Find the area of ΔGHI, to the nearest 10th of a square inch.

baherus [9]

Answer:

7.5 inches

Step-by-step explanation:

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3 years ago

Gina works at a diner. She earns $6 each hour plus tips. I. One week she worked 37 hours a week and earned $43 in tips. How much

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Answer:

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Step-by-step explanation:

The answer is $265 (how much did she make altogether)

The equation is x=6h+6

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a local sports team sells 6 tickets for $3,8 tickets for $4,and 10 tickets for $5.write a rule and equation to find out the cost

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3 years ago

Using the following equation, find the center and radius: x2 −2x + y2 − 6y = 26 (5 points)

Lisa [10]

Answer:

Center: (1,3)

Radius: 6

Step-by-step explanation:

Hi there!

$x^2-2x + y^2 - 6y = 26$

Typically, the equation of a circle would be in the form $(x-h)^2+(y-k)^2=r^2$ where $(h,k)$ is the center and $r$ is the radius.

To get the given equation $x^2-2x + y^2 - 6y = 26$ into this form, we must complete the square for both x and y.

<u>1) Complete the square for x</u>

Let's take a look at this part of the equation:

$x^2-2x$

To complete the square, we must add to the expression the square of half of 2. That would be 1² = 1:

$x^2-2x+1$

Great! Now, let's add this to our original equation:

$x^2-2x+1+y^2-6y = 26$

We cannot randomly add a 1 to just one side, so we must do the same to the right side of the equation:

$x^2-2x+1+y^2-6y = 26+1\\x^2-2x+1+y^2-6y = 27$

Complete the square:

$(x-1)^2+y^2-6y = 27$

<u>2) Complete the square for y</u>

Let's take a look at this part of the equation $(x-1)^2+y^2-6y = 27$ :

$y^2-6y$

To complete the square, we must add to the expression the square of half of 6. That would be 3² = 9:

$y^2-6y+9$

Great! Now, back to our original equation:

$(x-1)^2+y^2-6y+9= 27$

Remember to add 9 on the other side as well:

$(x-1)^2+y^2-6y+9= 27+9\\(x-1)^2+y^2-6y+9= 36$

Complete the square:

$(x-1)^2+(y-3)^2= 36$

<u>3) Determine the center and the radius</u>

$(x-1)^2+(y-3)^2= 36$

$(x-h)^2+(y-k)^2=r^2$

Now, we can see that (1,3) is in the place of (h,k). 36 is also in the place of r², making 6 the radius.

I hope this helps!

3 0

3 years ago

Read 2 more answers

Simplify 12cm to 2.5mm

julia-pushkina [17]

Given:

12cm to 2.5mm

To find:

The simplified for of given statement.

Solution:

We know that,

1 cm = 10 mm

12 cm =120mm

We have,

12cm to 2.5mm

It can be written as

$\dfrac{12\ cm}{2.5\ mm}=\dfrac{120\ mm}{2.5 mm}$

$\dfrac{12\ cm}{2.5\ mm}=\dfrac{120}{2.5}$

$\dfrac{12\ cm}{2.5\ mm}=48$

Therefore, the value of 12 cm to 2.5 mm is 48 or 48:1.

7 0

3 years ago