Answer:
a)
We know that:
a, b > 0
a < b
With this, we want to prove that a^2 < b^2
Well, we start with:
a < b
If we multiply both sides by a, we get:
a*a < b*a
a^2 < b*a
now let's go back to the initial inequality.
a < b
if we now multiply both sides by b, we get:
a*b < b*b
a*b < b^2
Then we have the two inequalities:
a^2 < b*a
a*b < b^2
a*b = b*a
Then we can rewrite this as:
a^2 < b*a < b^2
This means that:
a^2 < b^2
b) Now we know that a.b > 0, and a^2 < b^2
With this, we want to prove that a < b
So let's start with:
a^2 < b^2
only with this, we can know that a*b will be between these two numbers.
Then:
a^2 < a*b < b^2
Now just divide all the sides by a or b.
if we divide all of them by a, we get:
a^2/a < a*b/a < b^2/a
a < b < b^2/a
In the first part, we have a < b, this is what we wanted to get.
Another way can be:
a^2 < b^2
divide both sides by a^2
1 < b^2/a^2
Let's apply the square root in both sides:
√1 < √( b^2/a^2)
1 < b/a
Now we multiply both sides by a:
a < b
Answer:
I would say C but i dont know
Step-by-step explanation:
Answer:
para el primer dibujo seria 1/12
para el segundo dibujo seria 1/16
para el tercer dibujo seria 1/10, pero tengo dudas con esta porque no se ve toda la figura.
Step-by-step explanation:
Answer:
A sampling distribution of the sample proportion with n = 20 and p = 0.8
Step-by-step explanation:
We are given that
The probability of tails of a weighted coin, p=0.8
n=20
We have to find the type of distribution is simulated if this procedure repeated 75 times .
Random variable is a proportion of number of tails therefore, type of distribution is sampling distribution of the sample proportion.
We have n=20 and p=0.8
Hence, we can say that type of distribution is simulated is given by
A sampling distribution of the sample proportion with n = 20 and p = 0.8
