Answer:
463833
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Medium
Solution
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In △ABD and △ACD, we have
DB=DC ∣ Given
∠ADB=∠ADC ∣ since AD⊥BC
AD=AD ∣ Common
∴ by SAS criterion of congruence, we have.
△ABD≅△ACD
⇒AB=AC ∣ Since corresponding parts of congruent triangles are equal
Hence, △ ABC is isosceles.
4 first rows have 6
5th row has 4
there are 28 computers
90 volume because 3 multiples by 30 = 90
Answer:
C
Step-by-step explanation:
5+2y+3z=5+3z+2yA
Intercambie los lados para que todos los términos de las variables estén en el lado izquierdo.
5+3z+2yA=5+2y+3z
Resta 5 en los dos lados.
3z+2yA=5+2y+3z−5
Resta 5 de 5 para obtener 0.
3z+2yA=2y+3z
Resta 3z en los dos lados.
2yA=2y+3z−3z
Combina 3z y −3z para obtener 0.
2yA=2y
Anula 2 en ambos lados.
yA=y
Divide los dos lados por y.
y
yA
=
y
y
Al dividir por y, se deshace la multiplicación por y.
A=
y
y
Divide y por y.
A=1
Answer: 18 1/6 feet
Step-by-step explanation:
From the question, we are informed that the rectangular sand box has a length of 5 1/3 feet and a width of 3 3/4 feet.
The perimeter would be calculated as:
= 2(length + width)
= 2( 5 1/3 + 3 3/4)
= 2( 5 4/12 + 3 9/12)
= 2( 8 13/12)
= 2 (9 1/12)
= 2 × 9 1/12
= 2 × 109/12
= 218/12
= 18 2/12
= 18 1/6 feet