theta is in the fourth quadrant where the cosine is positive.
the third side in the triangle = sqrt (4 - 2) = sqrt2
So sin theta = -sqrt2/2 = Second choice (negative because sine is negative in 4th quadrant)
tan theta = - sqrt2 / sqrt2 = -1
We have that (x) + (x+2) + (x+4) = 126 so 3x + 6 = 126 can be used to find the first integer.
3x + 6 = 126
3x = 120
x = 40
The numbers are 40, 42, 44
Answer:
The maximum value of the table t(x) has a greater maximum value that the graph g(x)
Step-by-step explanation:
The table shows t(x) has two (2) x-intercepts: t(-3) = t(5) = 0. The graph shows g(x) has two (2) x-intercepts: g(1) = g(5) = 0. Neither function has fewer x-intercepts than the other.
The table shows the y-intercept of t(x) to be t(0) = 3. The graph shows the y-intercept of g(x) to be g(0) = -1. The y-intercepts are not the same, and that of t(x) is greater than that of g(x).
The table shows the maximum value of t(x) to be t(1) = 4. The graph shows the maximum value of g(x) to be g(3) = 2. Thus ...
the maximum value of t(x) is greater than the maximum value of g(x)
Answer:
100
Step-by-step explanation:
In economics, for a firm to earn optimum profits, it is important that it achieves a long run equilibrium. We can transfer the same to the case here that for the club to achieve optimum attendance, it must achieve long- run equilibrium attendance.
The condition for Long Run Equilibrium is that:
Club meeting attendance this week = Club meeting attendance next week
X = 80 + 0.20X
X - 0.20X = 80
X = 80/0.8
X = 100.
The long- run equilibrium attendance for this club is 100.
Z scores are (age - mean) / std dev
= 23 - 27 / 2 = -2 and 27-27 / 2 = 0
Using the standard normal tables we find the required percentage is 47.73%
