I have included attachment below
so since a rhombus is 2 pairs of paralell sides, we can cut it into 4 triangles
we can see that we can take the bottom 2 triangles and put them on top to get a rectangle that is width 21 and height 32/2 (16=height
area of rectangle=legnth times width=16 times 21=336 m^2
answer is 336 m^2
The standard form of a quadratic equation is
, while the vertex form is:
, where (h, k) is the vertex of the parabola.
What we want is to write
as
First, we note that all the three terms have a factor of 3, so we factorize it and write:
.
Second, we notice that
are the terms produced by
, without the 9. So we can write:
, and substituting in
we have:
![\displaystyle{ y=3(x^2-6x-2)=3[(x-3)^2-9-2]=3[(x-3)^2-11]](https://tex.z-dn.net/?f=%5Cdisplaystyle%7B%20y%3D3%28x%5E2-6x-2%29%3D3%5B%28x-3%29%5E2-9-2%5D%3D3%5B%28x-3%29%5E2-11%5D)
.
Finally, distributing 3 over the two terms in the brackets we have:
![y=3[x-3]^2-33](https://tex.z-dn.net/?f=y%3D3%5Bx-3%5D%5E2-33)
.
Answer:
Y=9.25 because inorder to solve this we need to first take 5*.3 which equals 1.5 now that we have this we can move on we now have the equation 1.5 + 2y = 20 so now we need to continue working on getting y by it self so we subtract 1.5 from each side and then that leaves us with 2y=18.5 now we divide by 2 which leaves us with y=9.25 enjoy=)
Answer:
I think it's AB=BC.
Step-by-step explanation:
*I'm not in college, nor anywhere near college-level math, just a heads-up.*
Anyway, here's what I think. I turned my head around a bit to different angles, and I noticed the angle AB is the exact same length as BC, and both make the triangle a right angle. Try it if ya want, and see what happens. Sorry if this's wrong. I do hope it helps!
Answer:54?
Step-by-step explanation:
