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ira [324]
3 years ago
13

3x+y=8________(1) and x²+xy=6________(2) solve this​

Mathematics
2 answers:
abruzzese [7]3 years ago
7 0

Answer:

[3, -1] \\ [1, 5]

Step-by-step explanation:

{3x + y = 8 >> y = -3x + 8

{x² + xy = 6

{x}^{2}  + x[-3x + 8] = 6 \\ {x}^{2}  -3{x}^{2}  + 8x = 6 \\ -2{x}^{2} + 8x = 6 \\  \\ -2{x}^{2} + 8x - 6 \\ [-2{x}^{2} - 6x] - [2x - 6] \\  \\ -2x[x + 3] - 2[x + 3] \\  \\ -[2x + 2][x + 3] = 0 \\  \\  1, \:  3 = x

You plug these back into both equations above to get both y-coordinates of -1 and 5:

-1, \: 5 = y

I am joyous to assist you anytime.

romanna [79]3 years ago
6 0

Answer:

In first equation if we put the value of x and y (x=2,y=2)than,

3x+y=8

3×x+y=8

3×2+2=8

6+2=8

8=8

in second equation the value of x=2,y=1

x2+xy=6

x2+x×y=6

4+2×1=6

4+2=6

6=6

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Naiomis fish is 40 mm long her guinea pigis 25cm long
dimaraw [331]

Answer:

1,000

Step-by-step explanation:

If your asking for the area you multiply 40 times 25

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3 years ago
How to graph 3 points <br> f (x) = -2x + 5
Kisachek [45]
The first one is 0,5 the second one is 1,3 last one is 2,1 
5 0
3 years ago
Please help me with this ​
MissTica

Answer:

For the question on the right, I assume b is the exponential factor, or growth factor.

Step-by-step explanation:

Linear:

Y=aX + b\\(X, Y) = (0, 15) => b = 15\\(X,Y) = (1, 12) => a = -3\\Y = -3X + 15

You can find the equation by using two points and the equation for a line.

Exponential:

Y = a^{bX+c}\\(X, Y) = (0, 81) => a^{c} = 81 => a^{c} = 3^{4} => a=3, c=4\\(X, Y) = (1, 27) => a^{b+c} = 27 => a^{b}a^{c} = 27 => a^{b} = \frac{27}{81} = \frac{1}{3} => b=-1\\Y = 3^{-X+4}

6 0
2 years ago
Verify that the points are the vertices of a parallelogram and find its area. (2,-1,1), (5, 1,4), (0,1,1), (3,3,4)
Gelneren [198K]

Answer:

Area = 13.15 square units

Step-by-step explanation:

Let the given vertices be represented as follows:

A(2, -1, 1) = 2i - j + k

B(5, 1, 4) = 5i + j + 4k

C(0, 1, 1) = 0i + j + k

D(3, 3, 4) = 3i + 3j + 4k

(i) Let's calculate the vectors of all the sides:

\\AB = B - A =  (5i + j + 4k) - (2i - j + k)

AB = 5i + j + 4k - 2i + j - k                 [Collect like terms]

AB = 3i + 2j + 3k

BC = C - B =  (0i + j + k) - (5i + j + 4k)

BC = 0i + j + k - 5i - j - 4k                 [Collect like terms]

BC = -5i + 0j - 3k

CD = D - C =  (3i + 3j + 4k) - (0i + j + k)

CD = 3i + 3j + 4k - 0i - j - k                [Collect like terms]

CD = 3i + 2j + 3k

DA = A - D =  (2i - j + k) - (3i + 3j + 4k)

DA = 2i - j + k - 3i - 3j - 4k                [Collect like terms]

DA = -i - 4j - 3k

AC = C - A =  (0i + j + k) - (2i - j + k)

AC = 0i + j + k - 2i + j - k                [Collect like terms]

AC = -2i + 2j

BD = D - B = (3i + 3j + 4k) - (5i + j + 4k)

BD = 3i + 3j + 4k - 5i - j - 4k                [Collect like terms]

BD = -2i + 2j

(ii) From the results in (i) above, we can deduce that;

AB = CD This implies that AB || CD  [AB is parallel to CD]

AC = BD This implies that AC || BD  [AC is parallel to BD]

(iii) Therefore, ABDC is a parallelogram since opposite sides (AB and CD) are parallel. Hence, the points are vertices of a parallelogram

<u>Now let's calculate the area</u>

To find the area of the parallelogram, we find the magnitude of the cross product of any two adjacent sides.

In this case, we'll choose AB and AC

Area = |AB X AC|

Where;

AB X AC = \left[\begin{array}{ccc}i&j&k\\3&2&3\\-2&2&0\end{array}\right]

<u></u>

AB X AC = i(0 - 6) - j(0 + 6) + k(6 + 4)

AB X AC = - 6i - 6j + 10k

|AB X AC| = \sqrt{(-6)^2 + (-6)^2 + (10)^2}

|AB X AC| = \sqrt{172}

|AB X AC| = 13.15

Area = 13.15 square units.

<u></u>

<u></u>

<u>PS: </u> ACBD is also a parallelogram. The diagram has also been attached to this response.

6 0
3 years ago
The mean of a normally distributed dataset is 12, and the standard deviation is 2.
madam [21]
NormalCdf(-2,2,0,1)=.9545
95.45%
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3 years ago
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