Answer: 1, 2, 4, or 5
Step-by-step explanation:
The relationship in #3 is a function because all the x values are distinct, that is, none are repeated. (Y values don't matter.)
A function will not repeat any x values so if your goal is for the relationship in #4 to NOT be a function, repeat one of the x values. Any one will work.
Answer:
㏒e(x)= 5
Step-by-step explanation:
Answer:
ans= 45.6
Step-by-step explanation:
I think the ans is 45.6
I hope it will help u...
he elements of the Klein <span>44</span>-group sitting inside <span><span>A4</span><span>A4</span></span> are precisely the identity, and all elements of <span><span>A4</span><span>A4</span></span>of the form <span><span>(ij)(kℓ)</span><span>(ij)(kℓ)</span></span> (the product of two disjoint transpositions).
Since conjugation in <span><span>Sn</span><span>Sn</span></span> (and therefore in <span><span>An</span><span>An</span></span>) does not change the cycle structure, it follows that this subgroup is a union of conjugacy classes, and therefore is normal.
Answer: (x+y)-6
Step-by-step explanation:
i think lol
