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Nadya [2.5K]
2 years ago
14

Find the area of the circle. 8 m

Mathematics
1 answer:
slava [35]2 years ago
6 0

Answer:

\pi \: r ^{2}

this your formula

and your answer is 201.142cm square

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Decimals between 10 15 with an interval of 0.75 between each pair of decimals
aleksley [76]
Should be <span>10.75, 11.5, 12.25, 13, 13.75, 14.5</span>
5 0
3 years ago
Read 2 more answers
Help how to solve! 24=3r divided by 4
zhenek [66]

24=3r/4

Multiply both sides by 4

24=(3r)/4

(24)*(4)=(3r/4)*(4)

96=3r

Flip the equation

3r=96

Divide both sides by 3

3r/3=96/3

r=32

Now lets check if the answer is good

24=3(32)/4

24= 96/4

24=24

You see , the answer is good .


I hope that's help ! Let me know .

6 0
2 years ago
We know that y=mx+b is the formula we use for lines. Is the value of "m" considered to be a term, a coefficient or a factor?
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4 0
3 years ago
The value of 4 in 3,492 is how many times the value of 4 in 704?
Norma-Jean [14]
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4 0
3 years ago
What is the partial fraction decomposition of StartFraction 8 x + 19 Over (x + 8) (x minus 1) EndFraction? StartFraction 3 Over
hoa [83]

The partial fraction decomposition is \frac{8x + 19}{(x + 8)(x - 1)} = \frac{5}{x + 8} + \frac{3}{x - 1}

<h3>How to determine the decomposition?</h3>

The fraction is given as:

\frac{8x + 19}{(x + 8)(x - 1)}

Split the fraction as follows:

\frac{8x + 19}{(x + 8)(x - 1)} = \frac{A}{x + 8} + \frac{B}{x - 1}

Take the LCM

\frac{8x + 19}{(x + 8)(x - 1)} = \frac{Ax -A + Bx + 8B}{(x + 8)(x -1)}

Cancel the common factors

8x + 19 = Ax - A + Bx + 8B

By comparison, we have:

Ax + Bx = 8x

-A + 8B = 19

This gives

A + B = 8

-A + 8B = 19

Add both equations

9B = 27

Divide by 9

B = 3

Substitute B = 3 in A + B = 8

A + 3 = 8

Solve for A

A = 5

So, we have:

\frac{8x + 19}{(x + 8)(x - 1)} = \frac{5}{x + 8} + \frac{3}{x - 1}

Hence, the partial fraction decomposition is \frac{8x + 19}{(x + 8)(x - 1)} = \frac{5}{x + 8} + \frac{3}{x - 1}

Read more about partial fraction at:

brainly.com/question/12783868

#SPJ1

6 0
2 years ago
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