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lyudmila [28]
4 years ago
10

Correct answer will be marked brainlest​

Mathematics
2 answers:
lesya692 [45]4 years ago
8 0
It would be 7/8 because there is 7 filled in out of 8 ANDWER: 7/8
Roman55 [17]4 years ago
3 0
The correct answer is 7/8
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The sales tax on a table saw is $10.20. What is the purchase price of the table saw if the sales tax rate is 8.5%
lara31 [8.8K]
120$
you set up a proportion, multiplying the $10.20 by 100 then divide by 8.5
7 0
3 years ago
: West Gorham High School is to be located at the population center of gravity of three communities: Westbrook, population 16,00
xenn [34]

Answer:

  (a) 43.6490°N, 70.3928°W

  (b) Baker's Field

Step-by-step explanation:

The locations are all within a 7-mile square, so we will make the assumption of a flat Earth with parallel longitude lines. Then the "central" location will be the weighted average of the latitude and longitude coordinates.

<h3>(a)</h3>

Total population is 16000 +22000 +36500 = 74,500. For purposes of the arithmetic, we will subtract 43 from latitude and 70 from longitude, then multiply each fraction by 10. Similarly, we will divide each population by 1000.

The weighted average location is found from ...

  (16/74.5)(6.769, 3.717) +(22/74.5)(5.781, 3.222) +(36.5/74.5)(6.795, 4.447)

  = (1.4537, 0.7983) +(1.7071, 0.9515) +(3.3291, 2.1787) = (6.490, 3.928)

The center of gravity is about 43.6490°N, 70.3928°W.

__

<h3>(b)</h3>

The coordinate differences from the center of gravity are (in (°lat, °long)) ...

  Baker's Field: (0.0294, -0.0101)

  Lonesome Acres: (-0.1371, -.0072)

Clearly, Baker's field is closer to the site of part (a).

_____

<em>Additional comment</em>

Distance calculations could be refined further by considering that a degree of longitude at this latitude represents about 0.72 times the distance of a degree of latitude. In this problem, the location of Lonesome Acres has a latitude difference that is several times any of the other coordinate differences, so it is clearly much farther away from the desired location.

The calculations done here are a sort of first-level approximation. The least-significant digits in the coordinates represent a distance of less than 50 feet. If you really want accuracy to that level, then the (approximately) spherical shape of the Earth needs to be accounted for. As a second-level approximation, some reference point needs to be identified, and coordinates in miles (or feet) need to be expressed in relation to that reference. The best accuracy would be obtained using spherical trigonometry to identify the distances.

We expect any school that is constructed to be somewhat larger than 50 feet in any direction, so accuracy to the 4th decimal place in these locations is probably not required--except to satisfy some answer-checker.

5 0
3 years ago
Mia got $80 for her birthday and spent $60. What percent of her birthday money does she have left
max2010maxim [7]

Answer:

16 percent is left

Step-by-step explanation:

20/100×80

Hope it helps!!

4 0
3 years ago
Evaluate.
Radda [10]

Step-by-step explanation:

-| 12/3 - 1| 2-(-3)

-|12-3/3|5

-5|9/3|

-5|3|

-5×3 & -5×-3

-15 & 15

I think it is the answer

6 0
2 years ago
Find the area of the triangle whose vertices are (0,4) , (0,0) and (2,0) by plotting them on graph
Luden [163]

Refer to the attached image. Since one vertex is the origin and the other two lay on the coordinate axes, the triangle is a right triangle. This means that, if we consider AB to the be base, AC is his height, and vice versa.

Anyway, it means that the area is given by

A = \cfrac{\overline{AB}\times\overline{AC}}{2}

Since AB is a horizontal segment and AC is a vertical segment, their length is given by the absolute difference of the non-constant coordinate: points A and B share the same x coordinate, so we subtract the y coordinates:

\overline{AB} = |2-0| = |2| = 2

The opposite goes for AC: points A and C share the same y coordinate, so we subtract the x coordinates:

\overline{AC} = |4-0| = |4| = 4

So, the area is

A = \cfrac{2\times 4}{2} = 4

4 0
3 years ago
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