All categories

3 years ago

What is the solution to the inequality |X-4 <3?

Mathematics

1 answer:

s2008m [1.1K]3 years ago

4 0

Answer:

x > 1 or x < 7

Step-by-step explanation:

| x - 4 | < 3

± ( x - 4 ) < 3

There are two possible cases

( x - 4 ) < 3 or - ( x - 4 ) < 3

x - 4 < 3 or - x + 4 < 3

x < 3 + 4 or 4 - 3 < x

x < 7 or 1 < x

x > 1 or x < 7

Therefore option 4 is correct.

You might be interested in

How to simplify this?<br>(3a-b)+2a

taurus [48]

Combine like terms

3a + 2a = 5a

5a - b

5a - b is your answer

hope this helps

4 0

2 years ago

Read 2 more answers

A box contains 3 coins. One coin has 2 heads and the other two are fair. A coin is chosen at random from the box and flipped. If

Blababa [14]

Answer: Our required probability is $\dfrac{1}{2}$

Step-by-step explanation:

Since we have given that

Number of coins = 3

Number of coin has 2 heads = 1

Number of fair coins = 2

Probability of getting one of the coin among 3 = $\dfrac{1}{3}$

So, Probability of getting head from fair coin = $\dfrac{1}{2}$

Probability of getting head from baised coin = 1

Using "Bayes theorem" we will find the probability that it is the two headed coin is given by

$\dfrac{\dfrac{1}{3}\times 1}{\dfrac{1}{3}\times \dfrac{1}{2}+\dfrac{1}{3}\times \dfrac{1}{2}+\dfrac{1}{3}\times 1}\\\\=\dfrac{\dfrac{1}{3}}{\dfrac{1}{6}+\dfrac{1}{6}+\dfrac{1}{3}}\\\\=\dfrac{\dfrac{1}{3}}{\dfrac{2}{3}}\\\\=\dfrac{1}{2}$

Hence, our required probability is $\dfrac{1}{2}$

No, the answer is not $\dfrac{1}{3}$

5 0

2 years ago

Is a number that is multiplied by a variable.

Nimfa-mama [501]

The answer would be yes

7 0

2 years ago

Read 2 more answers

What is the value of x?

Nesterboy [21]

This is a special 60-30-90 triangle, and the angle measure of x is $4 \sqrt{3} .$

8 0

3 years ago

Read 2 more answers

If -3=4x+7 what is x?

velikii [3]

4x+7=-3
4x=-3-7
4x=-10
X=-10/4
X=-2.5

4 0

2 years ago

Read 2 more answers