Given expression is 35, 36, 37, 38...
First term a = 35
Common difference d = 36-35 = 1
Nth term of arithmetic sequence is:


To find the 100th term, substitute n = 100


Correct option is B
<span>Let p, np be the roots of the given QE.So p+np = -b/a, and np^2 = c/aOr (n+1)p = -b/a or p = -b/a(n+1)So n[-b/a(n+1)]2 = c/aor nb2/a(n+1)2 = cor nb2 = ac(n+1)2
Which will give can^2 + (2ac-b^2)n + ac = 0, which is the required condition.</span>
The correct answer is 41/25
Answer: (B) 189 4 cm3 is the correct answer
Step-by-step explanation: