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olga nikolaevna [1]
2 years ago
7

If x² = 64, then 1/3 + x⁰​

Mathematics
2 answers:
Alenkasestr [34]2 years ago
8 0

Answer:

\huge\boxed{\bf\:\frac{4}{3} }

Step-by-step explanation:

If, x^{2} = 64, then,

x^{2} = 64\\x = \sqrt{64}\\x = (+/-)8

Now, remember that any number when folllowed by exponent 0 will always have its value as 1.

Then,

\frac{1}{3} + x^{0} \\ =\frac{1}{3} + (+/-8)^{0} \\= \frac{1}{3} + 1\\=\frac{1}{3} +\frac{3}{3} \:\:\:\: (LCM = 3)\\ \boxed{\bf\:\frac{4}{3} }

\rule{150pt}{2pt}

Elodia [21]2 years ago
5 0

Answer:

<u>4/3 or 1 1/3</u>

Step-by-step explanation:

<u>Finding x</u>

  • x² = 64
  • x = ±8

<u>Substitute in the equation</u>

  • 1/3 + (±8)⁰
  • 1/3 + 1
  • <u>4/3 or 1 1/3</u>
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A train leaves Zurich at 2240 and arrives in Paris at 0732. work out the time taken​
Alisiya [41]

The time taken to reach train from Zurich to Paris is 8 hours 52 minutes.

Step-by-step explanation:

          The given is,

                     Train leaves Zurich at 22:40

                     Train arrives Paris at 07:32

Step:1

          Time taken to reach from zurich to paris,

                            = Train leaves at Zurich - Train arrives at Paris

                            = 22:40 - 07:32

                            = 8.52 hours

Step:2  

         Time taken by train to reach from zurich to paris in minutes,

                           = 8.52 hours

                           = 4831 minutes 12 secs

Result:

        The time taken to reach train from Zurich to Paris is 8 hours 52 minutes, if a train leaves Zurich at 2240 and arrives in Paris at 0732.

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Step-by-step explanation:

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Can Someone tell me how to find a rate of change and an initial value
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First version one is the instantaneous rate of change. aka derivative. This one is found simply by taking the derivative of a function.

Second version is the average rate of change, which is found using the slope formula, (y₂ - y₁)/(x₂ - x₁)

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

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6 0
3 years ago
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David found and factored out the GCF of the polynomial 80b4 – 32b2c3 + 48b4c. His work is below. GFC of 80, 32, and 48: 16 GCF o
BlackZzzverrR [31]

Answer: The correct statements are

The GCF of the coefficients is correct.

The variable c is not common to all terms, so a power of c should not have been factored out.

David applied the distributive property.

Step-by-step explanation:

GCF = Greatest common factor

1) GCF of coefficients : (80,32,48)

80 = 2 × 2 × 2 × 2 × 5

32 = 2 × 2 × 2 × 2 × 2

48 = 2 × 2 × 2 × 2 × 3

GCF of coefficients : (80,32,48) is 16.

2) GCF of variables :(b^4,b^2,b^4)

b^4= b × b × b × b

b^2 = b × b

b^4 =b × b × b × b

GCF of variables :(b^4,b^2,b^4) is b^2

3) GCF of c^3 and c: c is not the GCF of the polynomial. The variable c is not common to all terms, so a power of c should not have been factored out.

4) 80b^4-32b^2c^3+48b^4c

=16b^2(5b^2-2c^3+3b^2c)

David applied the distributive property.

7 0
3 years ago
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