Find the area of all the separate figures and add them together
area of rectangle = length x width
11 x 3 = 33 ft
area of square = a^2
3^2 = 9ft
area of triangle = base x height over 2
11 x 3 = 33
33 over 2 = 16.5 ft
33 + 9 + 16.5 = 58.5 ft ^ 2
Answer:
Ba0.12 if b have x plus 5.10 need to be A
Answer:
There are 6,296 children at the carnival
Step-by-step explanation:
The number of each group of people can be expressed as;
Number of boys (b)+number of adults (a)=7,052
b+a=7,052....equation 1
Number of girls (g)=Number of adults (a)-756
g=a-756....equation 2
But Number of girls (g)=number of boys (b)
Replacing the value of b in equation 1 with that of g in equation 2;
(a-756)+a=7,052
a+a=7,052+756
2 a=7,808
a=7,808/2
a=3,904
Replace the value of a in equation 2 with 3,904
g=3,904-756
g=3,148
But since g=b
g=b=3,148
b=3,148
Total number of children=Total number of boys (b)+total number of girls (g)
Total number of children=b+g
where;
b=3,148
g=3,148
replacing;
Total number of children=(3,148+3,148)=6,296
There are 6,296 children at the carnival
The value is J = 1.71*10^-6 kmol/m^2.s
According to the given conditions we get,
The length the tube l= 0.20m
The diameter of the tube d= 0.01m
The total pressure inside the tube P= 101.32kPa
The partial pressure of CO2 at the first end is
P1= 456mm Hg = 60794.832 Pa
The partial pressure of CO2 at the other end is
P2= 76mm Hg = 10132.472 Pa
The temperature is T = 298 K
The diffusion coefficient D= 1.67* 10^-5 m^2/s
Generally the molar flux of CO2 is mathematically represented as
J= D{p1-p2} / R.T
Here R is the gas constant with value R= 8.314 j/kmol
So we get J= 1.71 * 10^-3 mol/m^2.sec
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