Answer:
1/216
Step-by-step explanation: I saw on another website that that’s the answer.
Write 3 four times and multiple them together. Then, write out 5 two times and multiple it together. Whatever those two answers are, subtract them
The inverse relation of the function f(x)=1/3x*2-3x+5 is f-1(x) = 9/2 + √(3x + 21/4)
<h3>How to determine the inverse relation?</h3>
The function is given as
f(x)=1/3x^2-3x+5
Start by rewriting the function in vertex form
f(x) = 1/3(x - 9/2)^2 -7/4
Rewrite the function as
y = 1/3(x - 9/2)^2 -7/4
Swap x and y
x = 1/3(y - 9/2)^2 -7/4
Add 7/4 to both sides
x + 7/4= 1/3(y - 9/2)^2
Multiply by 3
3x + 21/4= (y - 9/2)^2
Take the square roots
y - 9/2 = √(3x + 21/4)
This gives
y = 9/2 + √(3x + 21/4)
Hence, the inverse relation of the function f(x)=1/3x*2-3x+5 is f-1(x) = 9/2 + √(3x + 21/4)
Read more about inverse functions at:
brainly.com/question/14391067
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Answer:
Triangle KLM
Step-by-step explanation:
Firstly, we need to write the coordinates of triangle NPQ
We have this as;
(-7,-6) for N
(-4,-3) for P
(-4,-6) for Q
Now, we are going to use the given translation formula;
(x + 8, y + 1)
N’ will be (-7+ 8, -6 + 1) = (1,-5)
P’ will be (-4+ 8, -3+1) = (4,-2)
Q’ will be (-4+ 8, -6+1) = (4,-5)
Now, we need to find the triangle with the exact given transformation coordinates calculated above;
We have the triangle as;
KLM
With K as (1,-5) ; L as (4,-2) and ; M as (4,-5)
