Answer:
A) ERROR
B) ∠C = 26°
Step-by-step explanation:
Houston, We have a problem!!! too much information
If we had a legit triangle, the law of sines would hold
19/sin138 = 8/sin20
28.395 = 23.390
as this is NOT an equality, the triangle does not exist as described.
IF it did, we'd get different results depending on which set we used
∠F = 180 - 138 - 20 = 22°
Law of sines
19/sin138 = DE/sin22 ⇒ DE = 19sin22/sin138 = <u>10.63697...</u>
or
8/sin20 = DE/sin22 ⇒ DE = 8sin22/sin20 = <u>8.762211...</u>
If we attempt to use Law of cosines
DE² = 19² + 8² - 2(19)(8)cos22 = <u>11.9639...</u>
so really none is correct because we attempt to use trig calculations to a non-triangle.
12) AC² = 15² + 19² - 2(15)(19)cos120
AC = 29.51270...
29.51270 / sin120 = 15/sinC
C = arcsin(15sin120/29.51270) = 26.1142... <u>26°</u>
Answer:
2/3
8/12
Step-by-step explanation:
You just divide each numerator 4 (5÷4) and each denominator by 6 (8÷6) and see if the numbers are the same.
5÷4=1.25
8÷6=1.33
They are not equivalent, so 5/8 is not correct
2÷4=0.5
3÷6=0.5
They are equivalent, so 2/3 is correct
<u>Please</u><u> give</u><u> brainliest</u><u> if</u><u> I</u><u> helped</u><u>!</u><u> </u><u>:</u><u>)</u>
Answer:
−1
/2
qx+
1
/2
x-5
Step-by-step explanation:
Let's simplify step-by-step.
1
/2
x−7−
2q/
4
x−(−2)
=
1
/2
x+−7+
(−1/2)
qx+2
Combine Like Terms:
=
1
/2
x+−7+
(−1
/2
qx+2
=(
−1
/2
qx)+(
1
/2
x)+(−7+2)
=
−1
/2
qx+
1
2x+−5
Answer:
=
−1
/2
qx+
1
/2
x-5
HOPE THIS HELPS!!!!!! :)
<3333333333
Answer:
I just want points hahahaha
