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3 years ago

11

a farmer knows that 5 sheep produce about 25 pound of wool. which is the best estimate how much wool the farmer can expect to ge

t from her flock of 68 sheep

1 answer:

lesya692 [45]3 years ago

4 0

Answer:

340 pounds of wool

Step-by-step explanation:

If we take the estimate of 25 pounds for 5 sheep, you can guess that there is 5 pounds from each sheep. So, 5×68=340

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Sold the equation. Round to the nearest hundredth. <br><br>17 · <img src="https://tex.z-dn.net/?f=1.8%5E%7B-x%2B7%7D%20%3D%205"

svetlana [45]

Answer:

Final answer is approx x=4.26.

Step-by-step explanation:

Given equation is $1.8^{-x+7} = 5$

Now we need to solve equation $1.8^{-x+7} = 5$ and round to the nearest hundredth.

$1.8^{-x+7} = 5$

$\log(1.8^{-x+7}) = \log(5)$

$(-x+7)\log(1.8) = \log(5)$

$(-x+7) = \frac{\log(5)}{\log(1.8)}$

$(-x+7) = \frac{0.698970004336}{0.255272505103}$

$-x+7 = 2.73813274192$

$-x = 2.73813274192-7$

$-x =−4.26186725808$

$x =4.26186725808$

Round to the nearest hundredth.

Hence final answer is approx x=4.26.

4 0

3 years ago

Is x + 10 a factor of the function f(x) = x3 − 75x + 250? Explain.

PtichkaEL [24]

Yes. When the function f(x) = x3 – 75x + 250 is divided by x + 10, the remainder is zero. Therefore, x + 10 is a factor of f(x) = x3 – 75x + 250.

According to the remainder theorem when f(x) is divided by (x+a) the remainder is f(-a).
In this case,
f(x)=x^3-75x+250
(x+a)=(x+10)
Therefore, the remainder f(-a)=f(-10)

=x^3-75x+250
=(-10)^3-(75*-10)+250
=-1000+750+250
=1000-1000
=0.
The remainder is 0. So, (x+10) is a factor of x^3-75x+250.

8 0

3 years ago

Marisa gets paid $50 for 5 hours of work and charges an initial fee of $13

Vitek1552 [10]

Answer:

whats the question

10 dollars an hour ?

63 dollars total ?

Step-by-step explanation:

4 0

3 years ago

Find the minimum cost of producing 50,000 units of a product, where x is the number of units of labor (at $36 per unit) and y is

erastovalidia [21]

Answer:

Step-by-step explanation:

Given problem: C(x,y) = 36x + 48y

constraint: 100x^0.6y^0.4

Using langrange Multiplier,

36 = 0.6(100)x^-0.4y^0.4λ i

48 = 0.4(100)x^0.6y^-0.6λ ii

dividing the equations we have:

x = 2y

substituting into the constraint

p(x,y) = 100 *(2y)^0.6 y^0.4 = 100*2^0.6 *y

5000 = 151.572y

y = 329.876 labor units

x = 659.752 capital units

Minimum cost = 36(659.752) +48(329.876) = $39585.12

6 0

3 years ago

A tour operator has a bus that can accommodate 20 tourists. The operator knows that tourists may not show up, so he sells 21 tic

dalvyx [7]

Answer:

The expected revenue of the tour operator is 985.

Step-by-step explanation:

There are two outcomes:

Either less than 21 tourists show up and the operator does not have to pay anything. Or 21 tourists show up and the operator has to repay 100.

Anyways, initially he gets the price of all the tickets sold. That is 21 each at 50, so $R = 21*50 = 1050$ .

Then, we need to find the probability that all of the 21 tourists show up. In this case, we have to subtract 100 from the revenue.

Each tourist has a 0.02 probability of not showing up. This means that each has a 1-0.02 = 0.98 probability of showing up. So the probability P that all 21 tourists show up is $P = (0.98)^{21} = 0.6542$ .

So, the expected revenue of the tour operator is

$R = 1050 - 100P = 1050 - 100(0.6542) = 984.58$

Rounded up, the expected revenue of the tour operator is 985.

6 0

3 years ago