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bagirrra123 [75]
3 years ago
7

If 9<15mx-8<27, where m is a positive constant, what is the possible range of values of 8/3 -5mx?

Mathematics
2 answers:
tankabanditka [31]3 years ago
6 0
<h2>Answer:</h2>

The possible range of \dfrac{8}{3}-5mx is:

                   (-9,-3) i.e. -9

<h2>Step-by-step explanation:</h2>

We are given a set of inequalities of the form:

9

Now when we divide all of the inequality by 3 we get that:

\dfrac{9}{3}

Now when we multiply the inequality by -1 then the sign of the inequality gets interchanged.

i.e.

-3>-(5mx-\dfrac{8}{3})>-9\\\\i.e.\\\\-3>\dfrac{8}{3}-5mx>-9

i.e.

-9

Hence, the possible range of \dfrac{8}{3}-5mx is:

    (-9,-3) i.e. between -9 and -3 with -9 and -3 excluded from the range.

sweet [91]3 years ago
4 0
9<15mx-8<27
Divide the all by 3
3<5mx-8/3<9
After that times all by -1
-3<8/3-5mx<-9
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<h3>Word Problem Leading To Quadratic Equation.</h3>

The general formula for quadratic equation in a in standard form is

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Learn more about Quadratic Equation here: brainly.com/question/25841119

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