Please help, the brainiest will go to the one with a good answer.

Jessica had m beads. She used 18 of them to make a necklace for her mom. Then she used the rest to make k bracelets for her frie

Y_Kistochka [10]

The expression to represent this would be (m-18)/k.

We first subtract the 18 beads she used in her mother's bracelet from her beginning number, m. We then divide our result by k, the number of bracelets she made for her friends.

3 0

4 years ago

A bake sale earns 80$ from selling 50 brownies. Each brownie cost the same amount. How much was 1 brownie?

Nataly [62]

$1.60
Divide 80 by 50 to find the cost of one brownie which will then lead you to get you the answer of $1.60

3 0

3 years ago

Read 2 more answers

Consider the expression 2√3 cos(x)csc(x)+4cos(x)-3csc(x)-2 √ 3 This expression can be represented as the product of the factors.

Alla [95]

Answer with explanation:

The given expression is:

$2 \sqrt{3}\cos x * \csc x+4 \cos x-3 \csc x-2\sqrt{3}\\\\=2 \cos x*(\sqrt{3}*\csc x+2)-\sqrt{3}*(\sqrt{3}*\csc x+2)\\\\\rightarrow (2\cos x -\sqrt{3})*(\sqrt{3}*\csc x+2)\\\\\rightarrow (2\cos x -\sqrt{3})*(\sqrt{3}*\csc x+2)=0\\\\(2\cos x -\sqrt{3})=0 \wedge (\sqrt{3}*\csc x+2)=0$

$\cos x=\frac{\sqrt{3}}{2} \wedge \csc x=\frac{-2}{\sqrt{3}}\\\\x=\frac{\pi}{6},2\pi-\frac{\pi}{6}\\\\x=\frac{\pi}{6},\frac{11\pi}{6} \wedge x=\pi+\frac{\pi}{3} ,2\pi-\frac{\pi}{3}\\\\x=\frac{4\pi}{3},\frac{5\pi}{3}\\\\x={\frac{\pi}{6},\frac{11\pi}{6},\frac{4\pi}{3},\frac{5\pi}{3}}$

Option C

8 0

3 years ago

The heights (in inches) and pulse rates (in beats per minute) for a sample of 40 women were measured. Using technology with the

Viktor [21]

Answer:

There is not sufficient evidence to support the claim that there is a linear correlation between the heights and pulse rates of women

Step-by-step explanation:

The correlation coefficient between the variables h(height in inches) and pulse rates (in beats per minute) is 0.202

Sample size n=40

Level of significane alpha = 0.01

Create null and alternate hypothesis as:

H0: r=0

Ha: r not equal 0

(Two tailed test at 1% significance level)

Sample r = 0.202

r difference = 0.202

test statistic t = $\frac{r\sqrt{n-2} }{\sqrt{1-r^2} } \\=\frac{0.202(\sqrt{38} )}{\sqrt{0.9592} } \\=\frac{1.25}{0.9794} \\=1.271$

df =n-2 =38

t critical value for 0.01 and df =38 is 2.704

Since our test statistic lies below 2.704, we accept null hypothesis

There is not sufficient evidence to support the claim that there is a linear correlation between the heights and pulse rates of women

7 0

4 years ago

SOMEONE PLEASE HELP!!!Which of the following represents the synthetic division form of the long

UkoKoshka [18]

Answer:

Choice C

Step-by-step explanation:

When setting up synthetic division you do:

x-5=0

x=5

and get the numerator's coefficients:

1, -3, 4

so that's 5 | 1 -3 4

7 0

3 years ago

Read 2 more answers