<span>a
-7xy3 + 8x2y2 - + 4x4</span>
<h3>Radius = 14cm</h3>
Step-by-step explanation:
Let O be the centre of the circle. Since P and S are the points of contact of tangents AD and DC respectively, OP ⊥ AD and OS ⊥ DC
Also, AD ⊥ DC (given), therefore, OPDS is a square.
BR = BQ = 27cm...(tangents from an external point to a circle are equal in length)
therefore, CR = CB - BR = (38 - 27)cm = 11cm
SC = CR = 11 cm...(tangents from an external point) therefore, DS = DC - SC = (25 - 11) cm = 14 cm.
therefore,
Radius of a circle = OP = DS = 14 cm...(therefore, OPDS is a square).
<h3>Hope it helps you!! </h3>
This question is a little unclear. y= 4x - 3 is already in slope-intercept form. If you use (2,-3), then it would look like -3 = 4(2) - 3...
y= -4x² - 16x - 14
Take the coefficient of x² as the common factor
y = - 4(x² + 4x + 7/2)
Add (b/2)² to complete the square
y = - 4( x² + 4x + 2² - 2² + 7/2)
Complete the square
y = -4( (x + 2)² - 1/2)
Remove the bracket
y = -4(x + 2)² + 2
Answer: y = -4(x + 2)² + 2
Answer:
your answer is 5 friend!
Step-by-step explanation:
next time write it out like this....
(30/2)-(5x2)
just so it makes more sense byeeee friend
