Mike installed the window shown. How many square feet is the window? Use 3.14 for pi. Round to the nearest tenth.

Mathematics

1 answer:

Natali [406]3 years ago

3 0

Answer: 3.9ft²

Step-by-step explanation:

Find the area of the rectangle first:

= Length * Width

= 2 * 1.5

= 3 ft²

Find the area of the semi-circle by finding the area of a circle and dividing it by 2:

= πr²

= 3.14 * 1.5/2 * 1.5/2

= 1.76625‬ft²

Divide by 2:

= 1.76625‬/ 2

= 0.88 ft²

Add the area of the rectangle to the semi-circle:

= 3 + 0.88

= 3.9ft²

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There are 9 students in a class: 2 boys and 7 girls. If the teacher picks a group of 4 at random, what is the probability that e

notsponge [240]

Answer:

<h2>28% probability that every student in the group is a girl.</h2>

Step-by-step explanation:

In this problem we have independent events, that is, the event "picking a girl" doesn't affect an "picking a boy", also, picking picking a girl doesn't affect the probability of the other subjects.

So, the probability when the first girl is being picked is:

$P_{1}=\frac{7 \ girls}{9 \ students}$

Because among the total 9 students, there are 7 girls.

Now, after picking one girl, there remains 6 girls and 8 students to be picked. So, the probability of the second girl would be:

$P_{2}=\frac{6 \ girls}{8 \ students}$

Then, the probability of the third girl:

$P_{3}=\frac{5 \ girls}{7 \ students}$

The fourth girl probability:

$P_{3}=\frac{4 \ girls}{6 \ students}$

Therefore, the probability of picking all 4 girls would be the product of each probability, because events are independent (we use product when they are independent):

$P=\frac{7 \ girls}{9 \ students} \times \frac{6 \ girls}{8 \ students} \times \frac{5 \ girls}{7 \ students} \times \frac{4 \ girls}{6 \ students}\\P=\frac{5}{18}=0.28 \ (or \ 28\%)$