Answer: i believe it’s the second one !
Answer:
1) HNO3/H2SO4, 2) CH3CH2CH2Cl/AlCl3
Explanation:
Benzene is a stable aromatic compound hence it undergoes substitution rather than addition reaction.
When benzene undergoes substitution reaction, the substituent introduced into the ring determines the position of the incoming electrophile.
If I want to synthesize m-nitropropylbenzene, I will first carry out the nitration of benzene using HNO3/H2SO4 since the -nitro group is a meta director. This is now followed by Friedel Craft's alkykation using CH3CH2CH2Cl/AlCl3.
Answer: 1.10x10²³ atoms of C
110202600000000000000000 atoms C
Explanation:The solution process is shown below.
0.183 mole C x 6.022x10²³ atoms C / 1 mole C
= 1.10x10²³ atoms C
or 110202600000000000000000 atoms C
