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hammer [34]
3 years ago
10

True or false? My volume changed from 20L to 15L so my Temperature increased. True False

Chemistry
1 answer:
Mashcka [7]3 years ago
5 0

Answer: the answer is TRUE

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Round off or add zeros to the following calculated answers to give a final answer with three significant figures
sesenic [268]
In this case, 58.703 has five significant figures because the 3 at the end is significant and therefore makes the 0 significant as well. Since there are 5 significant figures, we need to round off the 7 to get 58.7, which has three significant figures.

Hope this helps.
8 0
3 years ago
Chemical equilibrium is reached when _____. hints chemical equilibrium is reached when _____. all of the reactants are converted
Aleonysh [2.5K]
Chemical equilibrium is a condition where the rate of product made is same as the rate of reactant made. Since the reaction to the left is same as the reaction to the right, so the amount of reactant and product will not be changed (doesn't mean that the amount is same, it just won't increase or decrease).
It's called equilibrium since there will be no change in their amount.
7 0
3 years ago
Identify which one is the reducing agent in this reaction
Romashka-Z-Leto [24]

Answer:

Na.

Explanation:

  • The oxidation-reduction reaction contains a reductant and an oxidant (oxidizing agent).
  • An oxidizing agent, or oxidant, gains electrons and is reduced in a chemical reaction. Also known as the electron acceptor, the oxidizing agent is normally in one of its higher possible oxidation states because it will gain electrons and be reduced.
  • A reducing agent (also called a reductant or reducer) is an element (such as calcium) or compound that loses (or "donates") an electron to another chemical species in a redox chemical reaction.

  • For the reaction:

<em>2Na + S → Na₂S.</em>

<em></em>

Na is oxidized to Na⁺ in (Na₂S) (loses 1 electron). "reducing agent".

S is reduced to S²⁻ in (Na₂S) (gains 2 electrons). "oxidizing agent".

6 0
4 years ago
In the Alkali metals what element is the same "Period" as the element Neon
Slav-nsk [51]

Answer:

Lithium

Explanation:

The answer is Lithium because the Alkali metals family is in the group 1A and the element neon is in the second period. If you look at the periodic table group 1A and the second period connects at the element Lithium.

7 0
4 years ago
A solution is prepared by dissolving 318.6 g sucrose (C12H22O11) in 4905 g of water. Determine the molarity of the solution
alexandr1967 [171]

The molarity of sucrose solution is 0.19 M.

The molarity of HCl is 12.8 M.

<u>Explanation:</u>

a. Molarity can be found by finding its moles and volume of water in L and then dividing both(moles divided by volume in Litres).

Mass of sucrose = 318. 6 g

Molar mass of sucrose = 342.3 g/mol

Moles = $\frac{mass}{molar mass}

       = $\frac{318.6 g}{342.3 g/mol}

      = 0.93 moles

Mass of water = 4905 g

Density of water = 1000 g/L

Volume = $\frac{mass}{density}

             = $\frac{4905 g }{1000 g/L}

          = 4.905 L

Now we can find the molarity = $\frac{moles}{Volume(L)}

                               =  $\frac{0.93 moles}{4.905 L}

                              = 0.19 M

So the molarity of sucrose solution is 0.19 M.

b. The molarity of HCl can be found as follows.

It is given that 39% HCl that means it contains 39 g of acid in 100 g of water.

Density of the solution is 1.20 g/mL, from this mass can be found as,

$\frac{1 L \times 1000 mL \times 1.20 g}{1 L \times 1 mL}

= 1200 g

Now we have to find out the amount of HCl in grams as,

$\frac{1200g \times 39 g HCl }{100 g solution}

= 468 g HCl

Now we have to find the number of moles,

moles = $\frac{468 g}{36.46 g/mol}

           = 12.8 moles

Molarity of HCl = $\frac{12.8 moles}{1 L }

                          = 12.8 M

So the molarity of HCl is 12.8 M.

6 0
3 years ago
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