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Blizzard [7]
3 years ago
6

Chlorofluorocarbons such as CCl2F and CCI,F, have been linked to ozone depletion in Antarctica. In 1994, these gases were found

in quantities of 261 and 509 parts per trillion by volume (World Resources Institute, World resources 1996-97). Compute the molar concentration of these gases under conditions typical of (a) the mid-latitude troposphere (10 °C and 1.0 atm) and (b) the Antarctic stratosphere (200 K and 0.050 atm). Hint: The composition of a mixture of gases can be described by imagining that the gases are separated from one another in such a way that each exerts the same pressure. If one gas is present at very low levels it is common to express its concentration as, for example, ‘x parts per trillion by volume Then the volume of the separated gas at a certain pressure is x x 10-2 of the original volume of the gas mixture at the same pressure. For a mixture of perfect gases, the volume of each separated gas is proportional to its partial pressure in the mixture and hence to the amount in moles of the gas molecules present in the mixture.

Chemistry
1 answer:
Ilya [14]3 years ago
4 0

Answer:

a) molarity of CCl3F = 1.12 × 10^-11 mol/dm³

Molarity of CCl2F2 = 2.20 × 10^-11 mol/dm³

B) molarity of CCL3F = 7.96 × 10 ^-13 mol/dm³

Molarity of CCl2F2 = 1.55 × 10^-12 mol/dm³

Explanation:

Using the ideal gas equation:

PV = nRT

Further explanations are found in the attachment below.

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The melting and boiling points of molecular compounds are generally quite low compared to those of ionic compounds. This is because the energy required to disrupt the intermolecular forces between molecules is far less than the energy required to break the ionic bonds in a crystalline ionic compound

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What coefficients are needed to balance the equation for the complete combustion of methane? Enter the coefficients in the order
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CH4 + 202 ---> 2H20 + CO2

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How many miles of glucose are in 19.1 g of glucose
geniusboy [140]

Answer:

did you mean moles? If so, answer is down below.

Explanation:

there are 0.106 moles of glucose in 19.1 g of glucose.

7 0
3 years ago
the copper anode is weighed before and after the electrolysis reation. if the copper anode is not completely dry when it is weig
Dmitrij [34]

Answer:

Faraday's constant will be smaller than it is supposed to be.

Explanation:

If the copper anode was not completely dry when its mass was measured, mass of the copper must be heavier than it should have been. Hence, the calculated Faraday’s constant would be smaller than it is supposed to be since when calculating Faraday’s Constant, the charge transferred is divided by the moles of electrons.

5 0
3 years ago
How would you prepare 500 mL of 0.360 M solution of CaCl2 from<br> solid CaCl2?
LenKa [72]

We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.

First, we need to determine the required moles of CaCl₂. We have 500 mL (0.500 L) of a 0.360 M solution (0.360 moles of CaCl₂ per liter of solution).

0.500 L \times \frac{0.360mol}{L} = 0.180 mol

Then, we will convert 0.180 moles to grams using the molar mass of CaCl₂ (110.98 g/mol).

0.180 mol \times \frac{110.98g}{mol} = 20.0 g

To prepare the solution, we weigh 20.0 g of CaCl₂ and add it to a beaker with enough distilled water to dissolve it. We stir it, heat it if necessary, and when we have a solution, we transfer it to a 500 mL flask and complete it to the mark with distilled water.

We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.

You can learn more about solutions here: brainly.com/question/2412491

4 0
1 year ago
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