Answer:
12 moles H
2
O
Explanation:
Your tools of choice for stoichiometry problems will always be the mole ratios that exist between the chemical species that take part in the reaction.
As you know, the stoichiometric coefficients attributed to each compound in the balanced chemical equation can be thought of as moles of reactants needed or moles of products formed in the reaction.
In your case, the balanced chemical equation for this synthesis reaction looks like this
2
H
2(g]
+
O
2(g]
→
2
H
2
O
(l]]
Notice that the reaction requires
2
moles of hydrogen gas and
1
mole of oxygen gas to produce
2
moles of water.
This tells you that the reaction produces twice as many moles of water as you have moles of oxygen gas that take part in the reaction.
You know that your reaction uses
6.0
moles of oxygen. Assuming that hydrogen gas is not a limiting reagent, you can say that the reaction will produce
6.0
moles O
2
⋅
2
moles H
2
O
1
moles O
2
=
12 moles H
2
O
Explanation:
Answer:
When stargazers go outside at night to look at the sky, they see the light from distant stars, planets, and galaxies. Light is crucial to astronomical discovery. Whether it's from stars or other bright objects, light is something astronomers use all the time. Human eyes "see" (technically, they "detect") visible light.
Mathematical formula of Ideal Gas Law is PV=nRT
where: P-pressure,
V-volume
n-number of moles; m/MW
T-Temperature
m-mass
d-density ; m/V
MW-Molecular Weight
R- Ideal Gas constant. If the units of P,V,n & T are atm, L, mol & K respectively, the value of R is 0.0821 L x atm / K x mol
Substituting the definitions to the original Gas equation becomes:
d= P x MW / (RxT)
Solution : d= .90atm x 28 g/mol (CO) / 0.0821Lxatm / mol x K x 323 K
d = 25.2 g / 26000 mL
d = .0.00096 g/mL is the density of CO under the new conditions
Answer:
Metre
Explanation:
the SI unit of length is <em>Me</em><em>tre</em>
Answer:
The longest wavelength is 2.19 × 10⁻⁷ m.
Explanation:
The work function (ф) is the minimum energy required to remove an electron from the surface of a metal. The minimum frequency required in a radiation to submit such energy can be calculated with the following expression.
ф = h × ν
where,
h is the Planck's constant (6.63 × 10⁻³⁴ J.s)
ν is the threshold frequency for the metal
In this case,
We can find the wavelength associated to this frequency using the following expression.
c = λ × ν
where,
c is the speed of light (3.00 × 10⁸ m/s)
λ is the wavelength
Then,