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Natasha_Volkova [10]

2 years ago

12

The perimeters of the two rectangles at right are equal. Write and solve an equation to find the value of x and the common perim

eter. (desperate need of help)

1 answer:

qaws [65]2 years ago

7 0

Answer:

write the expression for the perimeter of the 1st rectangle 6x

write the expression for the perimeter of the 2nd rectangle 4x + 30

write the equation 6x = 4x + 30

x= 15

perimeter = 90

Step-by-step explanation:

The perimeter is adding up all the sides of the rectangle.

So for the first one, we know two of the sides: x and 2x. The opposite sides have the same values. So the other two sides are x and 2x.

Therefore, the perimeter is

2x + x + 2x + x

or

6x

Similarly with the second rectangles:

(x+12) + (x+3) + (x+12) + (x+3)

Combine like terms

x + x + x + x + 12 + 3 + 12 + 3

4x + 30

Set these two equal to each other because the two perimeters are equal

6x = 4x + 30

Subtract 4x on both sides

2x = 30

Divide by 2 on both sides

x = 15

Check:

6(15) = 4(15) + 30

90 = 60 + 30

90 = 90

The common perimeter is

6*15 = 90 units

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Answer:

a) n = 1037.

b) n = 1026.

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In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

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(a) Assume that nothing is known about the percentage to be estimated.

We need to find n when M = 0.04.

We dont know the percentage to be estimated, so we use $\pi = 0.5$ , which is when we are going to need the largest sample size.

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 2.575\sqrt{\frac{0.5*0.5}{n}}$

$0.04\sqrt{n} = 2.575*0.5$

$(\sqrt{n}) = \frac{2.575*0.5}{0.04}$

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$0.04\sqrt{n} = 2.575*\sqrt{0.55*0.45}$

$(\sqrt{n}) = \frac{2.575*\sqrt{0.55*0.45}}{0.04}$

$(\sqrt{n})^{2} = (\frac{2.575*\sqrt{0.55*0.45}}{0.04})^{2}$

$n = 1025.7$

Rounding up

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<h3>What is a confidence interval of proportions?</h3>

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In which:

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