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Natasha_Volkova [10]
3 years ago
12

The perimeters of the two rectangles at right are equal. Write and solve an equation to find the value of x and the common perim

eter. (desperate need of help)

Mathematics
1 answer:
qaws [65]3 years ago
7 0

Answer:

write the expression for the perimeter of the 1st rectangle 6x

write the expression for the perimeter of the 2nd rectangle 4x + 30

write the equation 6x = 4x + 30

x= 15

perimeter = 90

Step-by-step explanation:

The perimeter is adding up all the sides of the rectangle.

So for the first one, we know two of the sides: x and 2x. The opposite sides have the same values. So the other two sides are x and 2x.

Therefore, the perimeter is

2x + x + 2x + x

or

6x

Similarly with the second rectangles:

(x+12) + (x+3) + (x+12) + (x+3)

Combine like terms

x + x + x + x + 12 + 3 + 12 + 3

4x + 30

Set these two equal to each other because the two perimeters are equal

6x = 4x + 30

Subtract 4x on both sides

2x = 30

Divide by 2 on both sides

x = 15

Check:

6(15) = 4(15) + 30

90 = 60 + 30

90 = 90

The common perimeter is

6*15 = 90 units

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Solution to the problem

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X \sim Binom(n=8, p=0.9)  

The probability mass function for the Binomial distribution is given as:  

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And for this case we want to find this probability:

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And we can find the individual probabilities using the probability mass function

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And replacing we got:

P(X \geq 7) = P(X=7) +P(X=8)=0.3826 +0.4305=0.8131

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