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Leto [7]
3 years ago
11

A fruit bowl contains apples, oranges, and bananas. The radius of one of the oranges is 1.25 inches. What is the approximate vol

ume of the orange? Use 3.14 for . A. 1.02 cubic inches B. 19.63 cubic inches C. 8.18 cubic inches D. 6.54 cubic inches
Mathematics
1 answer:
Elden [556K]3 years ago
3 0

Answer:

8.18 cubic inches

Step-by-step explanation:

An orange is a sphere so you will use the formula for the volume of a sphere.

V= 4 /3 * π * r^3       r^3= 1.25* 1.25 * 1.25= 1.953

V= 4/3* 3.14 * 1.953 = 8.176=8.18

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6=x/5 solve the question <br> X=
Sliva [168]

Answer:

x=30

Step-by-step explanation:

6 x 5 = 30

30/5 = 6

8 0
3 years ago
Out of 28 cookies, 3/4 are chocolate chip. How many cookies are chocolate chip?
Leviafan [203]

21 out of 28 cookies are chocolate chip

3 0
3 years ago
Read 2 more answers
The 10th term of an arithmetic proression is 68 and the common difference is 7 find the first term of the sequence
leonid [27]

Answer:

5

Step-by-step explanation:

first term + (10-1)7=68

first term= 68- 63=5

3 0
3 years ago
A population of insects grows exponentially, as shown in the table. Suppose the increase in population continues at the same rat
Ivanshal [37]

We are told that a population of insects grows exponentially and we are given a table of data about insect population growth. We are asked to find population of insects at the end of week 11.        

The initial insect population is 20 and at the end of 1st week population increases to 30.

Let us find growth percentage of insect  population,

\text{Growth percentage}=\frac{\text{Difference}}{Actual} \cdot100

\text{Growth percentage}=\frac{\text{30-20}}{20} \cdot100

\text{Growth percentage}=\frac{\text{10}}{20} \cdot100

\text{Growth percentage}=0.5 \cdot100=50

We can see that insect population is growing at rate of 50% per week.

Now let us write an exponential function for our population.

P(w)=20(1+0.50)^{w}, where P(w) represents population at the end of w weeks.

Let us substitute w=11 in our function to find insect population at the end of 11 weeks.

P(11)=20(1+0.50)^{11}

P(11)=20(1.50)^{11}

P(11)=20\cdot 86.49755859375

P(11)=1729.951171875\approx 1730

Therefore, population of insects at the end of 11th week will be 1730.  



7 0
4 years ago
Identify the center and radius of the circle (x-7)^2+(y-11)^2=36
OverLord2011 [107]

Answer:

Centre is (7,11)

Radius is 6

Step-by-step explanation:

The general equation for a circle is written in the form (x-a)^2+(y-b)^2=r^2 , where (a,b) is the centre of the circle, and r is the radius.

For your circle, (x-7)^2+(y-11)=36, we can compare it with the general equation to find the centre and radius.

-a = -7

-b = -11

r^2 = 36

Therefore, a=7, b=11 and r=6.

Centre at (a,b) which is (7,11) .

6 0
3 years ago
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