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GrogVix [38]
3 years ago
6

Explain the answer with briefs steps​

Mathematics
1 answer:
aliina [53]3 years ago
6 0

Step-by-step explanation:

steps are in picture above.

<u>N</u><u>o</u><u>t</u><u>e</u><u>:</u><u>i</u><u>f</u><u> </u><u>y</u><u>o</u><u>u</u><u> </u><u>n</u><u>e</u><u>e</u><u>d</u><u> </u><u>t</u><u>o</u><u> </u><u>ask</u><u> </u><u>a</u><u>n</u><u>y</u><u> </u><u>question</u><u> </u><u>p</u><u>l</u><u>e</u><u>a</u><u>s</u><u>e</u><u> </u><u>let</u><u> </u><u>me</u><u> </u><u>know</u><u>.</u>

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A Rectangle is removed from a right triangle to create the shaded region below. Find the area of the shaded region be sure to in
Scorpion4ik [409]

The given shapes area is found to be 4 square yards.

Step-by-step explanation:

Step 1; To determine the area of an indefinite shape we must divide it into the shapes that we know. The shape that is given can be split into a triangle with a rectangle in it.

Step 2; Any given triangles area is half the multiplication of its base value and its height value. In the given diagram, the base of the triangle measures a length of 5 yards and the length from base to top is 4 yards

Area of the triangle = \frac{1}{2} * base * height = \frac{1}{2} * 5 * 4 = 10 square yards.

The given rectangle measures a length of 3 yards and a width of 2 yards. The area of any given rectangle is the multiplication of its length and width.

Area of the rectangle = Length * Width = 3 yards * 2 yards = 6 square yards.

Step 3; To find the total area of the shape we must subtract the the rectangle's area from the triangle's area.

Area of given shape = Area of the triangle - Area of the rectangle.

Area of given shape = 10 square yards - 6 square yards = 4 square yards.

7 0
4 years ago
Help me !!! ASAP!!!!
natima [27]
X intercept is (14/9,0)
Y intercept is (0,-2)
4 0
3 years ago
Read 2 more answers
What is the exact volume of the sphere? 36.868π m³ 94.46π m³ 147.456π m³ 463.01π m³ Sphere with dotted line extending from middl
Bezzdna [24]
80% sure it b 94.46π m³
3 0
3 years ago
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N independent random samples of 10 men and 10 women in a coed basketball league, the numbers of points scored per season are giv
faltersainse [42]

Answer:

Step-by-step explanation:

Hello!

a)

To compare both datasets I've made a box plot for them.

The yellow one belongs to the points scored by the men and the green one is for the points scored by the women.

Women: The box seems symmetrical, the median and the mean (black square) are almost the same. The whiskers are almost the same length, you could say that in general the points scored by the women have a symmetrical distribution.

Men: The box looks a little skewed to the right, the median is closer to the 1st quantile and the mean is greater than the median. The whiskers are the same length, in general the distribution seems almost symmetrical.

b)

As you can see in the box plot  the median and mean of the points scored by the women are almost the same. Using the data I've calculated both values:

Me= 24.50

X[bar]= 23.80

The median divides the sample in halves (50-50),  it shows you where the middle of the distribution is.

The average shows you the value that centers the distribution, meaning, it is the value around which you'll find most of the data set. It summarizes best the sample information and therefore is a better measure of center.

c.

As you can see in the box plots, there are no outliers in both distributions.

An outlier is an observation that is significantly distant from the rest of the data set. They usually represent experimental errors (such as a measurement) or atypical observations. Some statistical measurements, such as the sample mean, are severely affected by this type of values and their presence tends to cause misleading results on a statistical analysis.

Considering the 1st quartile (Q₁), the 3rd quartile (Q₃) and the interquartile range IQR, any value X is considered an outlier if:

X < Q₁ - 1.5 IQR

X > Q₃ + 1.5 IQR

Or extreme outliers if:

X < Q₁ - 3 IQR

X > Q₃ + 3 IQR

For the women data set:

Q₁= 17; Q₃= 30; IQR= 30 - 17= 13

Lower outliers: X < Q₁ - 1.5 IQR= 17-1.5*13= -2.5 ⇒ The minimum value recorded is 03, so there are no outliers.

Upper outliers: X > Q₃ + 3 IQR= 30 + 1.5*13= 49.5 ⇒ The maximum value registered is 41, so there are no outliers.

I hope this helps!

6 0
3 years ago
Help please and thank you ​
Dominik [7]

Answer:

  D

Step-by-step explanation:

We assume the rotation R is <em>counterclockwise</em> 60°.

__

The exponent on R is the number of times it is applied. That is, R² = R(R(figure)). So, the composition is equivalent to R^(2-4) = R^-2.

When the exponent of R is negative, it is essentially the inverse function. That is, applying the function R to the result will give the figure you started with. Equivalently, it is rotation in the other direction.

  (\mathcal{R}^2\circ\mathcal{R}^{-4})(\text{figure})=\mathcal{R}^{-2}(\text{figure})=\text{figure rotated $120^{\circ}$ CW}

The point 120° clockwise from B is D.

The desired image point is D.

3 0
3 years ago
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