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Mademuasel [1]
3 years ago
6

The faces of a tetrahedron die are numbered 1 to 4. If each of the 4 sides is equally likely to land down, what is the probabili

ty that the 2 does not end up face down?
Mathematics
2 answers:
Marat540 [252]3 years ago
8 0
Hello!

If there is 4 faces and 1/4 chance of any side end up face down, we just have to decrease one chance, so, the chance of  the face "2" does not end up face down is equal the sum of the chances of the others faces end up face down, so, we have: 3/4.

Hugs!
egoroff_w [7]3 years ago
7 0

Answer:

3/4

Step-by-step explanation:

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Step-by-step explanation:

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lesantik [10]

Answer:

For tingle #1

We can find angle C using the triangle sum theorem: the three interior angles of any triangle add up to 180 degrees. Since we know the measures of angles A and B, we can find C.

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We cannot find any of the sides. Since there is noting to show us size, there is simply just not enough information; we need at least one side to use the rule of sines and find the other ones. Also, since there is nothing showing us size, each side can have more than one value.  

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In this one, we can find everything and there is one one value for each.

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Since we have a right triangle, we can find side c using the Pythagorean theorem

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cos(C)=\frac{2}{4}

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Again, we can find everything and there is one one value for each.

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A=180-(B+C)

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a=\frac{7}{tan(34.88)}

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The Minimum sample size table is attached below

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