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Mademuasel [1]
3 years ago
6

The faces of a tetrahedron die are numbered 1 to 4. If each of the 4 sides is equally likely to land down, what is the probabili

ty that the 2 does not end up face down?
Mathematics
2 answers:
Marat540 [252]3 years ago
8 0
Hello!

If there is 4 faces and 1/4 chance of any side end up face down, we just have to decrease one chance, so, the chance of  the face "2" does not end up face down is equal the sum of the chances of the others faces end up face down, so, we have: 3/4.

Hugs!
egoroff_w [7]3 years ago
7 0

Answer:

3/4

Step-by-step explanation:

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