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3 years ago

6

Answer it all please

1 answer:

fgiga [73]3 years ago

3 0

What do you need help with? it helps us to know the question!

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The amount of garbage, G produced by a city with population p is given by G = f(p). G is measured in tons per week, and p is mea

barxatty [35]

Alright, so this is simple.

P= 50,000 or 50 thousands

G= 13 Tons

The variable f isn't known.

So your equation would be 13 = 50 (f), if you were to put your known variables in the equation.

If you were to find variable f, you would divide 13 tons by 50,000 to get 0.00026 or in scientific notation: 2.6 x 10 (exponent(s):-4)

5 0

3 years ago

Somebody please help me out quick ??

scoundrel [369]

38 i think is correct

6 0

3 years ago

Read 2 more answers

Draw the next term if this represents an

Eva8 [605]

Answer:

keep stacking

Step-by-step explanation:

all it is doing is stacking

3 0

1 year ago

F(x) = 3x2²2 = 13

snow_lady [41]

Answer: 5/13

Step-by-step explanation:

$f(2)=\frac{3(2)^{2}-7}{4(2)^{2}-3}=\boxed{\frac{5}{13}}$

8 0

2 years ago

A perpendicular bisector, , is drawn through point C on .

Liula [17]

Answer:

The x-intercept of CD is B(18/5,0). The point C(32,-71) lies on the line CD.

Step-by-step explanation:

the x-intercept of CD is[ A(3,0) B(18/5,0) C(9,0) D(45/2,0) ] . Point [ A(-52,117) B(-20,57) C(32,-71) D(-54,-128) ] lies on CD.

Given :

CD is perpendicular bisector of AB.

The coordinates of point A are (-3, 2) and the coordinates of point B are (7, 6).

C is the midpoint of AB.

$C=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})=(\frac{7-3}{2},\frac{2+6}{2})=(2,4)$

The coordinates of C are (2,4).

Line AB has a slope of: $m_1=\frac{y_2-y_1}{x_2-x_1}=\frac{6-2}{7-(-3)}=\frac{4}{10}=\frac{2}{5}$

The product of slopes of two perpendicular lines is -1. Since the line CD is perpendicular to AB, therefore the slope of CD : $m_2=-\frac{5}{2}$

The point slope form of a line is given by:

$y-y_1=m(x-x_1)$

The slope of line CD is $-\frac{5}{2}$ and the line passing through the point (2,4), the equation of line CD can be written as:

$y-4=-\frac{5}{2}(x-2)\\y=-\frac{5}{2}x+5+4\\y=-\frac{5}{2}x+9 .... (1)$

The equation of CD is $y=-\frac{5}{2}x+9$

In order to find the x-intercept, put y=0.

$0=-\frac{5}{2}x+9\\\frac{5}{2}x=9\\x=\frac{18}{5}$

Therefore the x-intercept of CD is B(18/5,0).

Put x=-52 in eq(1).

$y=-\frac{5}{2}(-52)+9=139$

Put x=-20 in eq(1).

$y=-\frac{5}{2}(-20)+9=59$

Put x=32 in eq(1)

$y=-\frac{5}{2}(32)+9=-71$

Put x=-54 in eq1).

$y=-\frac{5}{2}(-54)+9=144$

Thus, only point (32,-71) satisfies the equation of CD. Therefore the point C(32,-71) lies on the line CD.

8 0

4 years ago