Photo math helps it worked for me so might help you :)
Answer:
10 9 8 7
Step-by-step explanation:
There are 10 choices for the first digit,
9 choices for the second digit,
8 choices for the third digit, and
7 choices for the fourth digit.
Using the fundamental counting principle, how many access codes are possible? 5,040
If the digits 0 through 9 could be repeated, how many access codes would be possible? 10,000
5x+61.50=78 and then subtract and get 5x=16.5 divide by 5 and get 3
Answer:
Step-by-step explanation: