Answer:
115200000 bits
Explanation:
Given Data:
Total Time = 3 minute = 3 x 60 sec = 180 sec
Sampling rate = 40,000 bits / sample
Each sample contain bits = 16 bits /sample
Total bits of song = ?
Solution
Total bits of song = Total Time x Sampling rate x Each sample contain bits
= 180 sec x 40,000 bits / sec x 16 bits /sample
= 115200000 bits
= 115200000/8 bits
= 14400000 bytes
= 144 MB
There are total samples in one second are 40000. Total time of the song is 180 seconds and one sample contains 16 bits. so the total bits in the song are 144 MB.
Answer:
The republicans storming the capitol
Explanation:
Answer:
I am not sure can you explain a little more
Answer:
Check the explanation
Explanation:
1.
System = 256Byte = 8 bit
Cache = 64B , block size = 16 byte.
A) Direct Mapped Cache:
Block offset = log (Block size) = log 16 = 4bit
Total # of block inside cache = 4.
Therefore index offset = log 4 = 2bit.
Remaining is tag bits.
Therefore tag bits = 8-(4+2) = 8-6 = 2 bits
Tag Index offset Block offset
(2 bits) (2 bits) (4 bits)
Fully associative cache :
In fully associative cache, any of main memory block can be placed anywhere in cache. Therefore index offset =0 bits.
Therefore tag bits = 8-block offset bit= 8-4 =4bits
Tag Block offset
(4 bits) (4 bits)
