Who is better at fortnite mc creamy or mau?

Mama L [17]

The answer is either B) or D) because I remember learning this and the keyword I remember is analogue

Hope this helps —- XoXo

3 0

3 years ago

Suppose you are consulting for a bank that's concerned about fraud detection, and they come to you with the following problem. T

iren [92.7K]

Answer:

Explanation:

( n cards are there initially )

we pick out the first card in random it takes n-1 comparisons to figure out

its Equivalence card - n-1 steps

Two cards have been eliminated ( this leaves us with 2 and n-2 cards)

we pick out the 2nd card in random it takes n-3 comparisons to figure out

its Equivalence card - n-3 steps

we continue to do this.. till all cards are exhausted ( leaves us with 2

and n-4 cards again)

the last comparison will

have

- n-(n-3)

the sum of all these steps - (n-1) + (n-3) + (n-5) + .........+

(n-(n-3))

if you draw this in the form of a tree.

n - n

2

n-2 - n

2

n-4 - n-2

2

n-6 - n-4

2

n-8 - n- 6

the height of the tree will be log n , sum @ each level is at most n

8 0

3 years ago

Write a program. in QBAsSIC

goblinko [34]

Answer:

The program is as follows:

5 INPUT A,B

6 PROD = A * B

7 PRINT PROD

8 TOTAL = A + B

9 PRINT TOTAL

10 DIFF = A - B

11 PRINT DIFF

12 END

Explanation:

This gets input for the two numbers

5 INPUT A,B

This calculates the product

6 PROD = A * B

This prints the calculated product

7 PRINT PROD

This calculates the sum

8 TOTAL = A + B

This prints the calculated sum

9 PRINT TOTAL

This calculates the difference

10 DIFF = A - B

This prints the calculated difference

11 PRINT DIFF

This ends the program

12 END

5 0

3 years ago

[1] Please find all the candidate keys and the primary key (or composite primary key) Candidate Key: _______________________ Pri

AVprozaik [17]

Answer:

Check the explanation

Explanation:

1. The atomic attributes can't be a primary key because the values in the respective attributes should be unique.

So, the size of the primary key should be more than one.

In order to find the candidate key, let the functional dependencies be obtained.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing -> Emp_ID

Course_ID -> Course Name

Course_Name -> Course_ID

Date_Completed -> Course_Name

Closure of attribute { Emp_ID, Date_Completed } is { Emp_ID, Date_Completed , Name, DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Name , Date_Completed } is { Name, Date_Completed , Emp_ID , DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { DeptID, Date_Completed } is { DeptID, Date_Completed , Emp_ID,, Name, , Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Marketing, Date_Completed } is { Marketing, Date_Completed , Emp_ID,, Name, DeptID , Salary, Course_Name, Course_ID}.

So, the candidate keys are :

{ Emp_ID, Date_Completed }

{ Name , Date_Completed }

{ DeptID, Date_Completed }

{ Marketing, Date_Completed }

Only one candidate key can be a primary key.

So, the primary key chosen be { Emp_ID, Date_Completed }..

2.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing -> Emp_ID

Course_ID -> Course Name

Course_Name -> Course_ID

Date_Completed -> Course_Name

3.

For a relation to be in 2NF, there should be no partial dependencies in the set of functional dependencies.

The first F.D. is

Emp_ID -> Name, DeptID, Marketing, Salary

Here, Emp_ID -> Salary ( decomposition rule ). So, a prime key determining a non-prime key is a partial dependency.

So, a separate table should be made for Emp_ID -> Salary.

The tables are R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

and R2( Emp_ID , Salary)

The following dependencies violate partial dependency as a prime attribute -> prime attribute :

Name -> Emp_ID

DeptID -> Emp_ID

Marketing -> Emp_ID

The following dependencies violate partial dependency as a non-prime attribute -> non-prime attribute :

Course_ID -> Course Name

Course_Name -> Course_ID

So, no separate tables should be made.

The functional dependency Date_Completed -> Course_Name has a partial dependency as a prime attribute determines a non-prime attribute.

So, a separate table is made.

The final relational schemas that follows 2NF are :

R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

R2( Emp_ID , Salary)

R3 (Date_Completed, Course_Name, Course_ID)

For a relation to be in 3NF, the functional dependencies should not have any transitive dependencies.

The functional dependencies in R1(Emp_ID, Name, DeptID, Marketing, Date_Completed) is :

Emp_ID -> Name, DeptID, Marketing

This violates the transitive property. So, no table is created.

The functional dependencies in R2 ( Emp_ID , Salary) is :

Emp_ID -> Salary

The functional dependencies in R3 (Date_Completed, Course_Name, Course_ID) are :

Date_Completed -> Course_Name

Course_Name -> Course_ID

Here there is a transitive dependency as a non- prime attribute ( Course_Name ) is determining a non-attribute ( Course_ID ).

So, a separate table is made with the concerned attributes.

The relational schemas which support 3NF re :

R1(Emp_ID, Name, DeptID, Course_ID, Marketing, Date_Completed) with candidate key as Emp_ID.

R2 ( Emp_ID , Salary) with candidate key Emp_ID.

R3 (Date_Completed, Course_Name ) with candidate key Date_Completed.

R4 ( Course_Name, Course_ID ). with candidate keys Course_Name and Course_ID.

6 0

3 years ago

What is displayed on the console when running the following program?

Andre45 [30]

Answer:

The answer is "Option A"

Explanation:

In the given java code, a class "Test" is defined, inside the main method try and catch block is used, inside the try block method "p()" is called, that print a message. in this block two catch block is used, that works on "NumberFormatException" and "RuntimeException". In the method "p" declaration, a string variable "s" is defined, that holds double value, that is "5.6", and converts its value into the wrong integer, and other wrong option can be described as follows:

In option B, it is wrong, it is not followed by after call method.
In option C, It is not followed by runtime exception, that's why it is incorrect.
Option D and Option E both were wrong because they can't give run time and compile-time error.

6 0

3 years ago