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3 years ago

Explain the trend in reactivity of the halogens 6 marks

Chemistry

1 answer:

mojhsa [17]3 years ago

4 0

Answer:

The reactivity of Group 7 elements decreases down the group. ... The electrons in the outer shell move further away from the nucleus as we go down the group and the attraction force between the electrons and the nucleus become weaker and weaker. This weaker attraction in the larger atoms makes it harder to gain electron.

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What is the identity of a 100. g sample of metal that, upon absorbing 4680 J of heat, increases in temperature by 52.0°C?

krok68 [10]

The metal is aluminium

<u>Explanation:</u>

Given:

Heat, q = 4680 J

Mass, m = 100g = 0.1kg

ΔT = 52°C

sample = ?

We know:

q = mcΔT

On substituting the value we get:

$4680 = 0.1 X c X(52)\\\\c = \frac{4680}{5.2} \\\\c = 900 J/Kg^oC$

Thus, the metal is aluminium which has a specific heat capacity of 900 J/kg°C

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4 years ago

Light travels as a/an___________

Debora [2.8K]

Answer:

D. Electromagnetic

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3 years ago

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3. How did your hypothesis work out? What was surprising in this experiment?

MAXImum [283]

Answer:

Whats the hypothesis and the experiment?

Explanation:

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3 years ago

Is ketchup a heterogeneous or homogeneous mixture? Explain your reasoning.

Norma-Jean [14]

Homogeneous because everything is mixed together evenly.

5 0

4 years ago

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An ideal gas at a given initial state expands to a fixed final volume. would the work be greater if the expansion occurs at cons

crimeas [40]

Answer:

Constant pressure

Explanation:

At constant pressure,

$w = -p\Delta V = -p(V_{f} - V_{i})$

At constant temperature,

$w = -RT \ln \left(\dfrac{V_{f}}{V_{i}} \right)$

1 mol of an ideal gas at STP has a volume of 22.71 L.

Let's compare the work done as it expands under each condition from an initial volume of 22.71 L.

Isobaric expansion

$w = -100p(V_{2} - 22.71}); \text{(1 bar$\cdot$L = 100 J)}$

A plot of -w vs V₂ gives a straight line (red) with a constant slope of 100 J/L as in the diagram below (Note that w is work done on the system, so -w is the work done by the system). \

Isothermal expansion

$w= -8.314 \times 273.15 \ln \left(\dfrac{V_{f}}{22.71} \right)\\\\= -2271 \left( \ln V_{f} -\ln22.71 \right)\\= -2271 \left(\ln V_{f} - 3.123 \right)\\= 7092 - 2271\ln V_{f}$

A plot of -w vs V₂ is a logarithmic curve. Its slope starts at 100 J/mol but decreases as the volume increases (the blue curve below).

Thus, the work done during an expansion at constant pressure is greater than if the system is at constant temperature.

4 0

4 years ago