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3 years ago

10. Name the one example of Analog computer

Mathematics

2 answers:

k0ka [10]3 years ago

8 0

Answer:

there are many types eg cosmic engine

BartSMP [9]3 years ago

6 0

Answer:

example of Analog computer=

Operational amplifiers

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A box of Georgia peaches has 3 bad and 12 good peaches. (a) If you make a peach cobbler of 12 peaches randomly selected from the

Eddi Din [679]

Answer:

a) 0.21% probability that there are no bad peaches in the peach cobbler.

b) 99.79% probability of having at least 1 bad peach in the peach cobbler

c) 7.91% probability of having exactly 2 bad peaches in the peach cobbler.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the peaches are chosen is not important. So the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

(a) If you make a peach cobbler of 12 peaches randomly selected from the box, what is the probability that there are no bad peaches in the peach cobbler?

Desired outcomes:

12 good peaches, from a set of 12. So

$D = C_{12,12} = \frac{12!}{12!(12 - 12)!} = 1$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{1}{455} = 0.0021$

0.21% probability that there are no bad peaches in the peach cobbler.

(b) What is the probability of having at least 1 bad peach in the peach cobbler?

Either there are no bad peaches, or these is at least 1. The sum of the probabilities of these events is 100%. So

p + 0.21 = 100

p = 99.79

99.79% probability of having at least 1 bad peach in the peach cobbler

(c) What is the probability of having exactly 2 bad peaches in the peach cob- bler?

Desired outcomes:

2 bad peaches, from a set of 3.

One good peach, from a set of 12.

$D = C_{3,2}*C_{12,1} = \frac{3!}{2!(3-2)!}*\frac{12!}{1!(12 - 1)!} = 36$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{36}{455} = 0.0791$

7.91% probability of having exactly 2 bad peaches in the peach cobbler.

3 0

3 years ago

Find the slope of the like y = 1/8x -1 anser choices -8/1 1/8 1 -1

otez555 [7]

Answer:

The equation is not linear. So the slope does not exist. Not linear.

Maybe you wrote the equation wrong? If so, let me know and I'll tell you what the answer is.

6 0

3 years ago

4. At Eagle Rock High School, the probability that a student takes theatre and choir is 0.052.

aleksklad [387]

Answer:

Step-by-step explanation:

Conditional probability is:

P(A given B) = P(A and B) / P(B)

Here, P(A and B) = 0.052 and P(B) = 0.17:

P(A given B) = 0.052 / 0.17

P(A given B) = 0.306

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3 years ago

Enya walked 2km 309m from school to the store. Then, she walked from the store to her home. If she walked a total of 5km, how fa

RSB [31]

Answer:

2 km 691 m

Step-by-step explanation:

5 km - 2 km 309 m

= 5000 m - 2309 m

= 2691 m

= 2 km 691 m

7 0

2 years ago

A bag contains 3 red marbles and 6 blue marbles. what is the probability of randomly selecting a red marble

DochEvi [55]

3/9 is your answer. 3+6=9 and there are 3 red marbles.

4 0

2 years ago

10. Name the one example of Analog computer​

10. Name the one example of Analog computer