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lisov135 [29]
3 years ago
9

An endpoint and midpoint are given. Find the coordinates of the other endpoint. endpoint: (2,6), midpoint: (5,12)

Mathematics
1 answer:
hammer [34]3 years ago
6 0

Answer:

I got (8, 18) for the other endpoint.

Hopefully this helps!

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Anyone know the answer?!
brilliants [131]

Answer:

a, 8,300

Step-by-step explanation:

6 0
3 years ago
How many 1/3 - hour shifts are in 3 hours
Alex Ar [27]
Each (1/3) shift would be 20 min. There are 3 shifts every hour and there are 3hrs.

3x3= 9 shifts
3 0
3 years ago
Cassandra assigns values to some of the measures of triangle ABC. If angle A measures 30°, a = 6, and b = 18, which is true?
Anna [14]

Answer:

The triangle does not exist because sin(A)/a can not be equal to sin(B)/b

Step-by-step explanation:

we know that

step 1

Find the measure of angle B

Applying the law of sines

\frac{sin(A)}{a}=\frac{sin(B)}{b}

we have

A=30\°

sin(30\°)=1/2

a=6\ units

b=18\ units

substitute

\frac{(1/2)}{6}=\frac{sin(B)}{18}

\frac{1}{12}=\frac{sin(B)}{18}

sin(B)=\frac{18}{12}

sin(B)=\frac{3}{2}=1.5

Remember that the value of sine can not be greater than 1

therefore

The triangle does not exist because sin(A)/a can not be equal to sin(B)/b

8 0
3 years ago
Find the distance between points P(3, -8) Q(7,4). Round to the nearest tenth if necessary
Gnom [1K]

To calculate the distance between two points, we can use a formula that is a variation Pythagorean Theorem. Look:


\mathsf{d=\sqrt{(x_Q-x_P)^2+(y_Q-y_P)^2}}


"d" represents the distance and coordinates are expressed as follows: (x, y)


Let's go to the calculations.


\mathsf{d=\sqrt{(x_Q-x_P)^2+(y_Q-y_P)^2}}\\\\ \mathsf{d=\sqrt{(7-3)^2+(4-(-8))^2}}\\\\ \mathsf{d=\sqrt{(4)^2+(4+8)^2}}\\\\ \mathsf{d=\sqrt{16+(12)^2}}\\\\ \mathsf{d=\sqrt{16+144}}\\\\ \mathsf{d=\sqrt{160}}\\\\ \mathsf{d=12,649110640673...}\\\\ \underline{\mathsf{d\approxeq12,6}}



The answer is 12,6 u.c.

3 0
3 years ago
7). A triangular prism has a volume of 16ft!. The area of the triangular base is 8ft. What is the height of the prism?
azamat
2 I think, I’m not sure tho
3 0
3 years ago
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