Answer:
4.5 % alloy
Step-by-step explanation:
Let x = amt of 30% alloy
The resulting total is to be 25 oz, therefore:
(25-x) = amt of 5% alloy:
A typical mixture equation:
.30x + .05(25-x) = .20(25)
.30x + 1.25 - .05x = 5 .30x - .05x = 5 - 1.25
.25x = 3.75
x = 3.75%2F.25
x = 15 oz of 30% alloy required
then
25-15 = 10 oz of 5% alloy:
Check solution
.30(15) + .05(10) = .20(25)
4.5 + .5 = 5
Step-by-step explanation:
the answer is c: 2..............
Answer:
2 - 
Step-by-step explanation:
Using the addition formula for tangent
tan(A - B) = 
and the exact values
tan45° = 1 , tan60° = , then
tan15° = tan(60 - 45)°
tan(60 - 45)°
= 
= 
Rationalise the denominator by multiplying numerator/ denominator by the conjugate of the denominator.
The conjugate of 1 + is 1 -
= 
← expand numerator/denominator using FOIL
= 
= 
= 
+ 
= 2 -
Answer:
40 so C would be your answer.
Answer:
In algebraic terms this means x-17>33
Step-by-step explanation:
to solve it x−17>33
1 Add 17 to both sides.
x>33+17
2 Simplify 33+17 to 50
x>50
