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Lostsunrise [7]
2 years ago
12

(a)/(2a)+(4)/(3a^(2)) ayuda por favor

Mathematics
1 answer:
Irina-Kira [14]2 years ago
5 0

Answer:

3a^2+8/6a^2

Step-by-step explanation:

there ya go hope this helps

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11) Which is an example of Associative Property of Addition ?
vlabodo [156]

Answer:

D. (3 + 4) + 9 = 3 + (4 +9)  represents the Associative Property of Addition.

Step-by-step explanation:

Associative Property of Addition states that for any groups of numbers, the order of addition does not matter.

or, for any numbers A, B and C

A + ( B +C)  = (A +B) + C

Here, D. (3 + 4) + 9 = 3 + (4 +9)  represents the Associative Property of Addition.

4 0
3 years ago
Using the unpaid balance​ method, find the current​ month's finance charge on a credit card account having the following transac
Reptile [31]

Answer:

33333333330000000000

5 0
3 years ago
The triangles shown are similar. What is the value of x?
Pavlova-9 [17]

Answer:

x = 10

Step-by-step explanation:

The bigger triangle is 2 times larger than the smaller triangle meaning all of the value of the smaller triangle are 2 times smaller than the bigger triangle and the bigger triangle is 2 times larger than the smaller triangle

6 0
2 years ago
Read 2 more answers
Which portion of the unit circle satisfies the trigonometric inequality cos^2theta + sin^2theta is greater than or equal to 1. A
liberstina [14]

Answer:

Only points on the circle satisfy the given inequality.

Step-by-step explanation:

Given: Unit circle

To find: portion of the unit circle which satisfies the trigonometric inequality \sin ^2\theta +\cos ^2\theta \geq 1

Solution:

In the given figure, OA = 1 unit (as radius of the unit circle equal to 1)

\sin \theta = side opposite to \theta/hypotenuse

\cos  \theta = side adjacent to \theta/hypotenuse

\sin \theta =\frac{AB}{AO}\\\sin \theta =\frac{AB}{1}\\AB=\sin \theta

\cos  \theta=\frac{OB}{AO}\\\cos \theta =\frac{OB}{1}\\OB=\cos \theta

So, coordinates of A = \left ( \cos \theta ,\sin \theta  \right )

For any point (x,y) on the unit circle with centre at origin, equation of circle is given by x^2+y^2=1

Put (x,y)=\left ( \cos \theta ,\sin \theta  \right )

\cos ^2\theta +\sin ^2\theta =1

So, (x,y)=\left ( \cos \theta ,\sin \theta  \right ) satisfies the equation x^2+y^2=1

For points  (x,y)=\left ( \cos \theta ,\sin \theta  \right ) inside the circle, \cos ^2\theta +\sin ^2\theta

For points  (x,y)=\left ( \cos \theta ,\sin \theta  \right ) outside the circle, \cos ^2\theta +\sin ^2\theta >1

So, only points on the circle satisfy the given inequality.

4 0
2 years ago
Read 2 more answers
What is the smallest value of y in the solution set to the system of equations below?
n200080 [17]

Answer:

The smallest value of y in the given two equations is 78

Step-by-step explanation:

Given as :

The two equation is given as :

y = x² + 6 x +23               ...........1

y = 18 x - 12.                     ..........2

Now, solving both equations

putting the value of y from eq 2 into eq 1

So,  x² + 6 x +23 = 18 x - 12

Or,  x² + 6 x +23 - 18 x + 12 = 0

Or, x² - 12 x + 35 = 0

Or, x² - 5 x - 7 x + 35 = 0

Or, x (x - 5) - 7(x - 5) = 0

Or, (x - 5) (x - 7) = 0

∴ x = 5 , 7

Now, for smallest value of y , take x = 5

∴ put the value of x in eq 2

So, y = 18 x - 12

I.e y = 18 × 5 - 12

Or, y = 90 - 12

∴   y = 78

Hence, The smallest value of y in the given two equations is 78 . answer          

7 0
3 years ago
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