Answer: Any real number x as long as
and 
In other words, anything but 0 or -2/3 is valid.
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Explanation:
Set the denominator equal to zero and solve for x
2(3x^2 + 2x) = 0
3x^2 + 2x = 0
x(3x + 2) = 0
x = 0 or 3x+2 = 0 .... zero product property
x = 0 or 3x = -2
x = 0 or x = -2/3
If either x = 0 or x = -2/3, then the denominator 2(3x^2 + 2x) will be zero. But recall that we cannot have zero in the denominator. Dividing by zero is not allowed. The expression is undefined when we divide by zero.
Therefore, we must exclude x = 0 and x = -2/3 from the domain. Any other real number is valid as an x input.
Answer: The answer is 27 good luck
Step-by-step explanation:
7
When you do 27 times x squared times z all over -3, then times that by x squared times z to the sixth power, you get -9x^4z^7
Answer:
yes
Step-by-step explanation:
because they both are equal.
Answer:
<h2>DOMAIN: The set of all real numbers except 0</h2>

Step-by-step explanation:
We have a faction.
We know: the denominator must be different from 0. Therefore
