3 years ago

Can someone help me! How do you find the area of any polygon??

Mathematics

2 answers:

zysi [14]3 years ago

5 0

Ya whats Ariana grande said

oee [108]3 years ago

4 0

To find the area of a regular polygon, all you have to do is follow this simple formula: area = 1/2 x perimeter x apothem. Here is what it means: Perimeter = the sum of the lengths of all the sides.

You might be interested in

Choose the correct simplification of the expression (c2)9.

Lapatulllka [165]

The correct simplification of the expression is 9c^2 i think.

5 0

3 years ago

Read 2 more answers

Please help properties of exponents

defon

Answer:

Step-by-step explanation:

3. $c^{11}$ add exponents

4. $m^{60}$ multiply exponents

5. $x^{6} y^{18}$ distribute and multiply exponents

6. $-21 a^{47} *b$ multiply and then add exponents

7. $100 a^{14} b^{4} c^{12}$ distribute and multiply exponents

8. $n^{22}$ multiply and then add exponents

3 0

3 years ago

What is the answer to this question with work I need it ASAS

PtichkaEL [24]

The answer is 7 3/4 inches.

I noticed the word "train" in the problem and I knew I had to help you! :)

6 0

2 years ago

Plz Help! I need this ASAP! I will give brainlest!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

viktelen [127]

7) 164.26

8)77.08

9)2405.364

steps for 7) attached

steps for 8)

7 0

3 years ago

Round up to the nearest hundredth

Shalnov [3]

$x^2+3x-5=0\\\\a=1;\ b=3;\ c=-5\\\\b^2-4ac=3^2-4\cdot1\cdot(-5)=9+20=29\\\\x_1=\dfrac{-b-\sqrt{b^2-4ac}}{2a};\ x_2=\dfrac{-b+\sqrt{b^2-4ac}}{2a}\\\\x_1=\dfrac{-3-\sqrt{29}}{2\cdot1}=\dfrac{-3-\sqrt{29}}{2}\approx-4.19\\\\x_2=\dfrac{-3+\sqrt{29}}{2\cdot1}=\dfrac{-3+\sqrt{29}}{2}\approx1.19$

5 0

3 years ago