$\left \{ {{y+4x=12} \atop {3y=8-12x}} \right. \\\\ \left \{ {{y=12-4x} \atop {3y=8-12x}} \right. \\\\3(12-4x)=8-12x\\\\36-12x=8-12x\\\\-12x+12x=8-36\\\\0\neq28\\\\There\ are\ no\ solutions.$

6 0

3 years ago

Help me with the problem plz 6p6

satela [25.4K]

i need more information to answer the question

5 0

3 years ago

Write sin(19°) in terms of cosine.

Leto [7]

Answer:

cos(71)

Step-by-step explanation:

Since 19° is less than 90, we can express this in terms of confunction.

sin(θ) = cos(90-θ)

sin(19) = cos(90-19)

sin(19) = cos(71)

3 0

3 years ago

What is 2∙ 2∙ 2∙ 2∙ 2∙ 2∙ 2∙ 2∙ 2 in exponential form?

Lubov Fominskaja [6]

Answer:

$2^9$

Step-by-step explanation:

Since there are nine 2s being multiplied by each other, we can represent this as $2^9$ .

5 0

3 years ago

Read 2 more answers