<u> 6 </u>- <u>5x</u> = <u> 6(4)</u><u>(x - 1) </u><u> </u>- <u>5x(4)(x - 1) </u>=<u> 24x - 24</u> = <u>20x² - 20x</u> = <u>20x² - 4x - 24</u>
x - 1 4 4(x - 1) 4(x - 1) 4x - 4 4x - 4 4x - 4
Answer: A: = −10x+4y+11
Step-by-step explanation:
Answer:
- ΔSQR ≅ ΔTQP by ASA congruence
- triangle congruence is needed before a claim based on that can be made
Step-by-step explanation:
1. The last step claims the lengths PQ and RQ are the same based on the congruence of triangles SQR and TQP. In order to make that claim, some step in the proof needs to claim that those triangles are congruent. That claim is the missing step:
ΔSQR ≅ ΔTQP --- ASA congruence postulate
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2. Without a claim of triangle congruence, the claim of triangle side congruence is unsupported. The proof must contain a claim that the triangles containing corresponding sides PQ and RQ are congruent.
Answer:
Seth has 21 nickels
Step-by-step explanation:
Let n represent the number of nickels. Since Seth has 8 more nickels than dimes, then (n-8) is the number dimes.
Nickel is worth 5 cents and dime is worth 10 cents. Thus, n nickels are worth 5n cents and (n-8) dimes are worth 10(n-8) cents. The total value of Seth's coins is $2.35 that is 235 cents, then

Solve this equation:

Answer:
b=-13d+28
Step-by-step explanation:
that's the answer friend