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AveGali [126]
2 years ago
13

Solve for x Enter your answer, as one inequality,in the box

Mathematics
2 answers:
AlekseyPX2 years ago
8 0

Answer:

x= (1,8)

Step-by-step explanation:

azamat2 years ago
6 0

Answer:

Step-by-step explanation:

-3≤ 6x - 9                 Add 9 to both sides

-3 + 9 ≤ 6x               Combine left

6 ≤ 6x                       Divide by 6

6/6 ≤ 6x/6

1 ≤ x

6x - 9 < 39               Add 9 to both sides

6x < 39 + 9              Combine

6x < 48                     Divide by 6

6x/6 < 48/6

x < 8

So the inequality is

1 ≤ x < 8

I think that is what you want. You have to express it as a combined inequality.

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Ba - ha = c <br> solve for a
PilotLPTM [1.2K]

Answer:

h = \frac{c}{b-h}

Step-by-step explanation:

Given

ba - ha = c ← factor out a from each term on the left side

a(b - h) = c ← divide both sides by (b - h)

a = \frac{c}{b-h}

7 0
2 years ago
A cargo truck weighs 8750 lb the weight limit for a certain bridge is 5 tons how many pounds of cargo can be added to the truck
Vaselesa [24]

Answer:

1,250 lbs

Step-by-step explanation:

There are 2,000 in 1 ton, so 5 * 2,000 = 10,000 lbs weight limit for the bridge.

10,000-8750 = 1,250 lbs can be added to the truck  before they reach the bridge weight limit.

7 0
3 years ago
Read 2 more answers
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const2013 [10]
<span>9·52 mm is the correct answer</span>
6 0
3 years ago
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A local food truck specializes in gourmet grilled cheese sandwiches. Each month, the owners of the truck have a constant total o
Serggg [28]

Answer:

A. (9 - 2.25)s ≥ 5,400

B. They will have to sell more than 800 sandwiches per month. I first started by solving the parentheses which is 6.75. Then I divided 5,400 by 6.75 to get 800.

C. It will now end up looking like this: (8 - 2.25)s ≥ 5,400. Then it will be 5.75. Then divide 5,400 by 5.75. Then you end up with 939.13. You have to round up when you are talking about inequalities with money so it will be 940. So they will have to sell 140 more sandwiches during that month.

Step-by-step explanation:

7 0
2 years ago
How to solve a quadratic equation that does not factor?
svlad2 [7]
Use the formula or complete the square.
The zeroes of the quadratic can be real and rational; real and irrational; complex conjugates.
If the quadratic is ax²+bx+c, x=(-b+√b²-4ac)/2a.
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If b² < 4ac the solutions are complex.
7 0
2 years ago
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