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3 years ago

Plllsssss help I’m doing test pls pls pls pls

Mathematics

1 answer:

Naddika [18.5K]3 years ago

6 0

Answer:

might be wrong..but i think its all real numbers

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What is an integer?

BartSMP [9]

Answer:

A integer is any number that is not either a decimal or a fraction (however, both 2.000 and 2/2 are integers because they can be simplified into non-decimal and non-fractional numbers), this includes negative numbers. A whole number is any positive number(0 through infinity) (including non-integers)

Step-by-step explanation:

it's basically a just any number but can't be a decimal or fraction

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3 years ago

Read 2 more answers

X+y=-3<br> X+Y=7 <br> no solution?

Pepsi [2]

Answer:

no solution

Step-by-step explanation:

x + y cannot be equal to both -3 and 7, so there is no solution.

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3 years ago

What is the y-intercept of y= -x -2

bija089 [108]

The y intercept is -2

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3 years ago

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About 33% of people who get their feet examined are found to have an ingrown toenail. What is the probability of a podiatrist ex

enot [183]

Answer:

The correct answer is 0.94147

Step-by-step explanation:

Let A denote the event that the podiatrist finds the first person with an ingrown toenail.

And (1 - A) denote the event that the podiatrist does not find the ingrown toenail.

While examining seven people, the podiatrist can find the very first person to have an ingrown toenail. Similarly he can find the second patient to have the ingrown toenail. Going in this way the probability of the first person to have an ingrown toenail is given by:

= A + (1 - A) × A + (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × (1 - A) × (1 - A) × (1 - A) × A.

= $\frac{1}{3} + \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} .$

= $\frac{1}{3} + \frac{2}{3} \frac{1}{3} + (\frac{2}{3}) ^{2} \frac{1}{3} + (\frac{2}{3})^{3} \frac{1}{3} + (\frac{2}{3})^{4} \frac{1}{3} + (\frac{2}{3})^{5} \frac{1}{3} + (\frac{2}{3})^{6} \frac{1}{3}.$

= 0.94147

We can also solve the above expression by using the geometric progression formula as well where common ratio is given by $\dfrac{2}{3}$ .

8 0

3 years ago

Pls help me factorize.Thanks!

Nat2105 [25]

We can change the sign of the second term, so that the two parenthesis are the same:

$6(a-1)b^3+3(1-a)b^2 = 6(a-1)b^3-3(a-1)b^2$

Now, both terms have in common a 3, becase the numeric factors are 3 and 6. If we factor the 3, we have

$6(a-1)b^3-3(a-1)b^2 = 3(2(a-1)b^3-(a-1)b^2)$

The parenthesis (a-1) is also in common, so we can factor it as well:

$3(2(a-1)b^3-(a-1)b^2) = 3(a-1)(2b^3-b^2)$

Finally, both terms in the parenthesis contain $b^2$ , because it's the power of b with the lowest exponent:

$3(a-1)(2b^3-b^2) =3(a-1)b^2(2b-1)$

So, the factorization is

$3b^2(a-1)(2b-1)$

You can swap the order of the four factors (3, b^2, a-1 and 2b-1) as you like: the multiplication is commutative.

5 0

3 years ago