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Scrat [10]
2 years ago
6

Y= ln(x^3 e^2x) (dy)/(dx)​

Mathematics
2 answers:
Anna71 [15]2 years ago
8 0

Answer:

2 + 3/x.

Step-by-step explanation:

y = ln(x^3 . e^(2x)

dy/dx = 1 /(x^3 e^2x) * (2x^3e^(2x)  + 3x^2 e ^(2x))

= 2 + 3/x.

uysha [10]2 years ago
7 0

Answer:

y =  ln( {x}^{3} . {e}^{2x} )

divide by In :

\frac{y}{ ln}  =  \frac{ ln( {x}^{3}. {e}^{2x}  ) }{ ln }  \\  \\  {e}^{y}  =  {x}^{3} . {e}^{2x}

find dy/dx:

{d( {e}^{y}) } = ( {x}^{3} . {e}^{2x} )dx \\  {e}^{y} dy =  \{(3 {x}^{2} . {e}^{2x} ) + ( {x}^{3} .2 {e}^{2x} ) \}dx \\  \\ {e}^{y}   \frac{dy}{dx}  =  {x}^{3}  + 3 {x}^{2}  + 3 {e}^{2x}  \\  \\  \frac{dy}{dx}  =  \frac{ {x}^{3} + 3 {x}^{2} + 3 {e}^{2x}   }{ {e}^{y} }  \\  \\  { \boxed{ \boxed{\frac{dy}{dx}  =  \frac{ {x}^{3} + 3 {x}^{2}   + 3 {e}^{2x} }{ {e}^{ {x}^{3}. {e}^{2x}  } }}}}

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Minchanka [31]

Answer:

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Step-by-step explanation:

(4-3) + (23) = 24

4 0
3 years ago
It takes 250 g of pasta and 240 ml of sauce to make one batch of spaghetti, and it takes 600g of pasta and 700ml of sauce to mak
klemol [59]

It takes 250 g of pasta and 240 ml of sauce to make one batch of spaghetti and it takes 600g of pasta and 700ml of sauce to make one batch of lasagna.

Case 1: Pasta

The chef wants to make spaghetti and lasagna using more than 4000 g of pasta.

S denote the number of batches of spaghetti he makes and L the number of batches of lasagna he makes.

So the equation becomes :

250S +600L > 4000

Case 2: Sauce

chef wants to make spaghetti and lasagna using more than 5000 ml of sauce.

S denote the number of batches of spaghetti he makes and L the number of batches of lasagna he makes.

So the equation becomes:

240S +700L > 5000

Answer :

The two equations are :

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6 0
3 years ago
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Determine the gradient of the straight line 2x-3y+9=0. Find the equation of the straight line through the origin which is perpen
frutty [35]

Answer: 3

x

−

2

y

−

15

=

0

Explanation:

We know that,

the slope of the line  

a

x

+

b

y

+

c

=

0

is  

m

=

−

a

b

∴

The slope of the line  

2

x

+

3

y

=

9

is  

m

1

=

−

2

3

∴

The slope of the line perpendicular to  

2

x

+

3

y

=

9

is  

m

2

=

−

1

m

1

=

−

1

−

2

3

=

3

2

.

Hence,the equn.of line passing through  

(

3

,

−

3

)

and

m

2

=

3

2

is

y

−

(

−

3

)

=

3

2

(

x

−

3

)

y

+

3

=

3

2

(

x

−

3

)

⇒

2

y

+

6

=

3

x

−

9

⇒

3

x

−

2

y

−

15

=

0

Note:

The equn.of line passing through  

A

(

x

1

,

y

1

)

and

with slope

m

is

y

−

y

1

=

m

(

x

−

x

1

)3

x

−

2

y

−

15

=

0

Explanation:

We know that,

the slope of the line  

a

x

+

b

y

+

c

=

0

is  

m

=

−

a

b

∴

The slope of the line  

2

x

+

3

y

=

9

is  

m

1

=

−

2

3

∴

The slope of the line perpendicular to  

2

x

+

3

y

=

9

is  

m

2

=

−

1

m

1

=

−

1

−

2

3

=

3

2

.

Hence,the equn.of line passing through  

(

3

,

−

3

)

and

m

2

=

3

2

is

y

−

(

−

3

)

=

3

2

(

x

−

3

)

y

+

3

=

3

2

(

x

−

3

)

⇒

2

y

+

6

=

3

x

−

9

⇒

3

x

−

2

y

−

15

=

0

Note:

The equn.of line passing through  

A

(

x

1

,

y

1

)

and

with slope

m

is

y

−

y

1

=

m

(

x

−

Explanation:

the equation of a line in  

slope-intercept form

is.

∙

x

y

=

m

x

+

b

where m is the slope and b the y-intercept

rearrange  

2

x

+

3

y

=

9

into this form

⇒

3

y

=

−

2

x

+

9

⇒

y

=

−

2

3

x

+

3

←

in slope-intercept form

with slope m  

=

−

2

3

Given a line with slope then the slope of a line

perpendicular to it is

∙

x

m

perpendicular

=

−

1

m

⇒

m

perpendicular

=

−

1

−

2

3

=

3

2

⇒

y

=

3

2

x

+

b

←

is the partial equation

to find b substitute  

(

3

,

−

3

)

into the partial equation

−

3

=

9

2

+

b

⇒

b

=

−

6

2

−

9

2

=

−

15

2

⇒

y

=

3

2

x

−

15

2

←

equation of perpendicular lineExplanation:

the equation of a line in  

slope-intercept form

is.

∙

x

y

=

m

x

+

b

where m is the slope and b the y-intercept

rearrange  

2

x

+

3

y

=

9

into this form

⇒

3

y

=

−

2

x

+

9

⇒

y

=

−

2

3

x

+

3

←

in slope-intercept form

with slope m  

=

−

2

3

Given a line with slope then the slope of a line

perpendicular to it is

∙

x

m

perpendicular

=

−

1

m

⇒

m

perpendicular

=

−

1

−

2

3

=

3

2

⇒

y

=

3

2

x

+

b

←

is the partial equation

to find b substitute  

(

3

,

−

3

)

into the partial equation

−

3

=

9

2

+

b

⇒

b

=

−

6

2

−

9

2

=

−

15

2

⇒

y

=

3

2

x

−

15

2

←

equation of perpendicular line

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