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Hunter-Best [27]
2 years ago
14

Which paragraph from the article is Best illustrated by image 2

Biology
1 answer:
pochemuha2 years ago
4 0

Answer:

please can you show the image

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1. The line "... form a more perfect
Minchanka [31]
The bill of right if am wrong I am so so sorry.
4 0
3 years ago
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Hypothesize whether prokaryotic cells might have been symbiotic before the evolution of eukaryotic
elena55 [62]
 <span>Two prokaryotes turning into a eukaryotic cell began with a process called

endosymbiosis. One large prokaryote engulfs (a process called

endocytosis) one small, aerobically respiring prokaryote. The small

prokaryote turned into a membrane-bound organelle, which prokaryotes do

not have, and like we know, only eukaryotes have membrane-bound

organelles. So that is how the eukaryotic cell structure evolved from

prokaryotic cells, meaning that before this evolution, they were most likely symbiotic.</span>
4 0
3 years ago
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Scientists say the planet Venus has a "runaway greenhouse effect." What condition would you expect on Venus as the result of a r
Inessa05 [86]

Answer:

I think the answer is

D. The planet is extremely hot.

Explanation:

It's because there is no water left on the surface, which helps cooling down the planet and the atmosphere contains thick and excessive carbon dioxide which traps the heat, causing the planet to heat up.

4 0
2 years ago
There is a population of alien dogs, species Dogus Cute-ee-us, that live on the planet Woof. Their genomes and biology are amazi
kupik [55]

Answer:

c. 1:4:6:4:1

Explanation:

The term quantitative heritability refers to the transmission of a phenotypic trait in which expression depends on the additive effect of a series of genes.  

Polygenic heritability occurs when a trait results from the interaction of more than one gene. And these genes can also have more than two alleles. The action of many genes and alleles can cause many different combinations that are the reason for genotypic graduation.  

Quantitative traits are those that can be measure, such as longitude, weight, eggs laid per female, among others. In the exposed example, the measurable trait is the dog´s friendliness. These characters do not group individuals by any precise and clear categories. Instead, they group individuals in many different categories that depend on how the genes were intercrossed and distributed during meiosis. The result depends on the magnitude in which each allele contributes to the final phenotype and genotype. When they interact, they create a gradation in phenotypes, according to the level of contribution.  

In the exposed example, each dominant allele contributes with a higher level of friendliness.    

  • aabb → 0 = Unfriendly/Loner (although not aggressive);
  • Aabb, aaBb → 1 = Somewhat friendly/shy;
  • AAbb, AaBb, aaBB → 2 = Friendly;
  • AABb, aABB → 3 = Very friendly;
  • AABB → 4 = Maximally friendly.

Cross: between two dihybrid friendly dogs

Parentals) AaBb    x    AaBb

Gametes) AB, Ab, aB, ab

                AB, Ab, aB, ab

Punnett square)   AB       Ab       aB       ab

                   AB   AABB   AABb  AaBB  AaBb

                    Ab   AABb    AAbb  AaBb  Aabb

                    aB   AaBB    AaBb   aaBB   aaBb

                    ab    AaBb    Aabb   aaBb   aabb

F1) 1/16 AABB ⇒ 4 = Maximally friendly

    4/16 AABb + AaBB ⇒ 3 = Very friendly

    6/16 AAbb + AaBb + aaBB ⇒ 2 = Friendly

    4/16 Aabb + aaBb ⇒ 1 = Somewhat friendly/shy

    1/16 aabb ⇒ 0 = Unfriendly/Loner

The Phenotypic ratio is 1:4:6:4:1

   

6 0
3 years ago
1. Why is the quadrat method useful for estimating snall populations? Explain why the same method would not be useful for counti
irga5000 [103]

Answer:

Quadrat method is used for estimating the number of individuals in an area. In this method, a large square area on the ground or water surface is marked, call it an enclave. The number of animals present in this enclave is counted. Then by assuming that the animals are less migratory and are uniformly distributed, their number for a large area is estimated by the use of unitary method of calculation. Example a 4 square feet area has 2 snails, then a 1000 square feet area will have (1000 x 2)/4, i.e, 500 snails in it. Fishes can be counted using this method only if they are confined in a small water body like a lake or a pond. Rivers are flowing so the fishes may move along its length which can give us an underestimate or an overestimate of their numbers. Sea has its depth and huge area, and fishes can be moving randomly in it. Hence this method will not work for river and sea fishes.

Explanation:

Hope this helps :D

7 0
2 years ago
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