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suter [353]
3 years ago
6

Find the midpoint (6,-7) and (4,1)

Mathematics
1 answer:
shepuryov [24]3 years ago
5 0

Answer:

(5, -3)

Step-by-step explanation:

let (x1, y1) = (6, -7) and (x2, y2) = (4,1)

(Xmidpoint, Ymidpoint) = ( (x1+x2) / 2, (y1+y2) / 2)

                                       = (5, -3)

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What is the slope and y-intercept of the following equation:<br> = 13 − 4 (show your work pls)
Colt1911 [192]

Answer:

Slope is 1/3

Y intercept is -4

5 0
3 years ago
The sum of an integer and 7 more than the next consecutive integer is 66. find the integer
Cloud [144]

If the sum of an integer and 7 more than the next consecutive integer is 66 then the integers are 29 and 30.

Given that the sum of an integer and 7 more than the next consecutive integer is 66.

Integer is a number that is written without a fraction component. It can be positive as well as negative.

let the first integer be x.

Consecutive integer will be x+1.

Sum of integer and 7 more than the next consecutive integer is 66.

Sum according to the given information=x+x+1+7

=2x+8

2x+8=66

2x=66-8

2x=58

x=58/2

x=29

Next integer=29+1-30.

Hence if the sum of an integer and 7 more than the next consecutive integer is 66 then the integers are 29 and 30.

Learn more about integers at brainly.com/question/17695139

#SPJ4

8 0
2 years ago
Fill in the blanks
brilliants [131]

Answer:

1. 100 which Is the easier one

2. 5

5 0
2 years ago
Part A: Solve -np 70 &lt; 40 for n. Show your work. (4 points)
ololo11 [35]
Part A:

 -np - 70 < 40
                          +70
                   -np < 110
                      -n < 110/p

Part B

      4w-7k=28
-7k=28-4w
7k=4w-28
k=4/7w-4
6 0
3 years ago
Write a quadratic equation ax²+ bx + C = 0, whose coefficients are a =-9, b = 0, c = -2
aksik [14]
<h3>ax² + bx + c = 0</h3>

<em>Let's write -9 where we see A</em><em>:</em>

<h3>-9x² + bx + c = 0</h3>

<em>Let's</em><em> </em><em>write</em><em> </em><em>0</em><em> </em><em>where</em><em> </em><em>we</em><em> </em><em>see</em><em> </em><em>B</em><em>:</em>

<h3>-9x² + 0.x + c = 0</h3>

<em>(</em><em>Since B = 0, when it is multiplied by x, it becomes 0 again</em><em>)</em>

<h3>-9x² + c = 0</h3>

<em>Let's</em><em> </em><em>write</em><em> </em><em>-2</em><em> </em><em>where</em><em> </em><em>we</em><em> </em><em>see</em><em> </em><em>C</em><em>:</em>

<h3>-9x² + -2 = 0</h3>

<em>Now we can move on to solving our equation</em><em>:</em><em>)</em>

<em>Let's put the known and the unknown on different sides:</em>

<em>(</em><em>-2 goes to the opposite side positively</em><em>)</em>

<h3>-9x² = 2</h3>

<em>(</em><em>i</em><em>t goes as a division because it is in the case of multiplying -9 across</em><em>)</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>

<h3>x² = 2/-9</h3>

<em>I could not find the rest of it, but I did not want to delete it for trying very hard. Sorry. It felt like we should take the square root, but I couldn't find it, maybe this can help you a little bit.</em>

<em>Please do not report</em><em>:</em><em>(</em>

<em>I hope I got it right, I'm trying to improve my English a little :)</em>

<h3><em>Greetings from Turke</em><em>y</em><em>:</em><em>)</em></h3>

<h3><em><u>#XBadeX</u></em></h3>
8 0
2 years ago
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