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3 years ago

Simplify the expression and write the result in standard form, a+bi. 6 - 8i / -2

Mathematics

1 answer:

gregori [183]3 years ago

4 0

Answer:

$\frac{6 - 8i}{ - 2} = \frac{6}{ - 2} - \frac{8i}{ - 2} (splitting \: denomenator) \\ = - 3 - - 4i \\ = - 3 + 4i \\ thank \: you$

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What is the slope-intercept form of the equation of the line with a slope of 3 and y-intercept at the origin (0,0)?

Viktor [21]

Answer:

Step-by-step explanation:

y=3x

8 0

2 years ago

The sum of a and 8<br> Shjdjjdjkdkdjdkd

katrin [286]

Answer:

a+8

Step-by-step explanation:

"sum" tells you to add the two numbers together.

8 0

3 years ago

HELP DUE IN 10 MINUTES!! WILL GIVE BRAINLEST IF CORRECT!!!!

Harman [31]

Answer:

<u>Given equation:</u>

y = 10x - 32

<u>To find the y-intercept, evaluate the equation with x = 0:</u>

y = 10*0 - 32
y = 0 - 32
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8 0

3 years ago

Ishaan is 222 times as old as Christopher. 353535 years ago, Ishaan was 777 times as old as Christopher.

klemol [59]

<h3><u>Question:</u></h3>

Ishaan is 2 times as old as Christopher. 35 years ago, Ishaan was 7 times as old as Christopher. How old is Christoper now?

<h3><u>Answer:</u></h3>

The present age of Christoper is 42 years old

<h3><u>Solution:</u></h3>

Given that Ishaan is 2 times as old as Christoper

Let the present age of Christoper be "x"

Then, Present age of Ishaan = 2 times as old as Christoper

present age of Ishaan = 2x

<em><u>35 years ago, Ishaan was 7 times as old as Christopher</u></em>

Age of Ishaan 35 years ago = Present age of Ishaan - 35

Age of Ishaan 35 years ago = 2x - 35

Similarly,

Age of christoper 35 years ago = Present age of christoper - 35

Age of christoper 35 years ago = x - 35

From given statement, 35 years ago, Ishaan was 7 times as old as Christopher

Age of Ishaan 35 years ago = 7 times the age of Christoper 35 years ago

(2x - 35) = 7(x - 35)

<em><u>Solve the above equation for "x"</u></em>

2x - 35 = 7x - 245

2x - 7x = -245 + 35

-5x = -210

Thus present age of Christoper is 42 years old

5 0

3 years ago

1st. (2 root 2 + root 3 ) ( 2 root 3 - root 2)

satela [25.4K]

Answer:

1st: 3*root6 + 5

2nd: 35*root2 + 115

3rd: 24*root2 - 20*root6 + 15*root3 - 18

4th: 17*root6 - 38

5th: 13*root10 - 42

Step-by-step explanation:

To simplify these expressions we need to use the distributive property:

(a + b) * (c + d) = ac + ad + bc + bd

So simplifying each expression, we have:

1st.

(2 root 2 + root 3 ) ( 2 root 3 - root 2)

= 4*root6 - 2*2 + 2*3 - root6

= 3*root6 - 4 + 9

= 3*root6 + 5

2nd.

(root 5 + 2 root 10) (3 root 5 + root 10)

= 3 * 5 + root50 + 6*root50 + 2*10

= 15 + 5*root2 + 30*root2 + 100

= 35*root2 + 115

3rd.

(4 root 6 - 3 root 3) (2 root 3 - 5)

= 8*root18 - 20*root6 - 6*3 + 15root3

= 24*root2 - 20*root6 + 15*root3 - 18

4rd.

(6 root 3 - 5 root 2 ) (2 root 2 - root 3)

= 12*root6 - 6*3 - 10*2 + 5*root6

= 17*root6 - 18 - 20

= 17*root6 - 38

5th.

(root 10 - 3 ) ( 4 - 3 root 10)

= 4*root10 - 3*10 - 12 + 9*root10

= 13*root10 - 30 - 12

= 13*root10 - 42

8 0

3 years ago